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Vikki [24]
3 years ago
14

Insert the parenthesis to make the equality right: 30-49/42/6*8=184

Mathematics
1 answer:
Alika [10]3 years ago
5 0
(6*8) is where the parentheses should go
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You buy books for 64 cents each, you plan to sell them for 75 cents each. You're left with 100 unsold books, and you lost $12. H
PSYCHO15rus [73]

The number of books sold is 473.

<u>Step-by-step explanation:</u>

  • The original cost of each book = $0.64
  • The selling price of each book = $0.75

The difference between the original price and selling price of the book gives the profit per book.

The profit of one book = Selling price - Original price

Let,

  • The total number of books be 'x'.
  • The number of books sold be 'y'.
  • The unsold books is 100.
  • The total profit is -12 because it was gone to a loss of $12.

Therefore, the equation is formed as

total Profit = 0.75y - 0.64x

⇒ 0.75y - 0.64x = -12 --------(1)

Total books = sold books + unsold books

x = y + 100

⇒ x-y = 100  -------(2)

Substitute x= 100+y in the eq(1),

0.75y - 0.64(100+y) = -12

0.75y - 64 -0.64y = -12

0.11y = -12 +64

y = 52 / 0.11

y = 472.7

y ≅ 473

The number of book sold is 473 books.

The total number of books is (100+473) = 573 books.

8 0
3 years ago
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0
3 years ago
COME ON PLSSSSSS HELP I'VE POSTED THIS BEFORE :(
mr Goodwill [35]

Here are your points (-9,-8), (-6,-2), (-2,-6)

5 0
3 years ago
HELP ME !!!!!!!!!!!!!!!!!!!!!!!!!!
gogolik [260]

Answer:

Bye

Step-by-step explanation:

Figure it out yourself

4 0
3 years ago
How do i simplify (8×102)⋅(2.5×102)
jenyasd209 [6]

Answer:

208,080

Step-by-step explanation:

(8x102)x(2.5x102)

102x8=816

102x2.5=255

(816)x(255)

816x255=208,080

4 0
3 years ago
Read 2 more answers
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