11. 4 + 10 = 14
25 - 14 = 11
You can solve this by putting the number of copies in the top part of the fraction. If you replace the one in the top part of 1/6 with 3, you get the fraction 3/6. Half of six is three and half of two is one, so both fractions are equal. You can test this be dividing the 3 in the top by 3 and the 6 in the bottom by three. Your result will be 1/2. Although there are three times ad many copies, each copy is three times as small, so it balances out.
Answer:
approx. 24.6 ft
Step-by-step explanation:
x=the distance of the fire from the base of the tower
200ft=the height of the tower
7 degrees=the angle of depression
Using these values you can draw a diagram that highlights that you need to use trig. to work out the answer.
Using Tan:
Tan 7=x/200 ft
multiply both sides by 200 ft
200*tan 7=24.55691218
approx. 24.6 ft
Answer: None of the above
Step-by-step explanation:
Given
![\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmathrm%7Bd%7D%20%5Cbar%7Bc%7D%7D%7B%5Cmathrm%7Bd%7D%20x%7D%3D-6x%5E%7B-2%7D%2B%5Cfrac%7B1%7D%7B6%7D)
![d\bar{c}=\left ( -6x^{-2}+\frac{1}{6}\right )dx](https://tex.z-dn.net/?f=d%5Cbar%7Bc%7D%3D%5Cleft%20%28%20%20-6x%5E%7B-2%7D%2B%5Cfrac%7B1%7D%7B6%7D%5Cright%20%29dx)
Now, integrating both sides
![\int d\bar{c}=\int \left ( -6x^{-2}+\frac{1}{6}\right )dx](https://tex.z-dn.net/?f=%5Cint%20d%5Cbar%7Bc%7D%3D%5Cint%20%5Cleft%20%28%20%20-6x%5E%7B-2%7D%2B%5Cfrac%7B1%7D%7B6%7D%5Cright%20%29dx)
![\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1](https://tex.z-dn.net/?f=%5Cbar%7Bc%7D%3D-6%5Cfrac%7Bx%5E%7B-2%2B1%7D%7D%7B-2%2B1%7D%2B%5Cfrac%7B1%7D%7B6%7Dx%2Bk_1)
![\bar{c}=6x^{-1}+\frac{1}{6}x+k_1](https://tex.z-dn.net/?f=%5Cbar%7Bc%7D%3D6x%5E%7B-1%7D%2B%5Cfrac%7B1%7D%7B6%7Dx%2Bk_1)