Answer:
y=-
x+
Step-by-step explanation:
First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find
m=(y2-y1)/(x2-x1)
=(2-(-4))/(-2-1)
=6/-3
=-2
in this equation the slope is 2, and to find the first equation, use y=mx+b
use the point (1, -4) to find b
-4=(2)(1)+b
-4=2+b
b=-6
the first equation of the line is y=2x-6
to find the x intercept of that line substitute 0 for y
0=2x-6
2x=6
x=3
the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2
for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b
y=mx+b
0=(-1/2)(3)+b
b=3/2
thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-
x+3/2
Answer:
2.2.6
Step-by-step explanation:
Answer:
I'd have to say, C: 13
Step-by-step explanation:
Answer: M < -3
.................................................
Step-by-step explanation:
4 - 3m > -5
4 - 3m > (-4 -5)
3m > -9
(3/3)m > (-9/3)
m<-3
X + 100 = 4x +49
x= 17
158+148+32+x = 360
338+x= 360
x= 22