Answer:
33%
Step-by-step explanation:
The logo can be divided into three...
1. The inner circle (or The White Circle)
2. Blue + White circle
3. The whole circle(The logo)
I will be calculating the area of each circle..
Area of circle = (pi)r²
pi = 22/7
The inner circle
radius = 4cm
Area = 22/7 × 4²
= 50.286 cm² or 50²/7 cm²
Blue + White Circle
radius = 4 + 3 = 7cm
Area = 22/7 × 7²
= 154 cm²
The whole circle
radius = 4 + 3 +3 = 10cm
Area = 22/7 × 10²
= 314.286 cm² or 314²/7 cm²
Area shaded blue =
Area of [(Blue + White circle) - (The white circle)]
= 154 - 50.286 = 103.714 cm² or 103.⁵/7 cm²
Percentage of logo shaded blue =
(Area shaded blue) / (Area of logo) × 100
= 103.714/314.286 × 100
= 32.9999%
= 33%
To solve this question, we first need to convert both of these values into mixed numbers. 5

becomes

and 4

becomes

. Now we have to find a LCD. An LCD for 4 and 8 is 8, so now we have to change

into something over 8.

becomes

when you multiply the fraction by the form of 1

. 34 + 43 = 77, so our answer is 77/8 which simplifies to
9
.
The answer is f(x)=x²+2x when evaluated with -3 gives you the value of 3
Let's check all functions.
1. The function f(x)=x²<span>+2x when evaluated with 3 gives you the value of 3:
Evaluated with x means that</span> x = 3.
f(3) = 3² + 2 * 3 = 9 + 6 = 15
15 ≠ 3, so, this is not correct.
2. f(x)=x²<span>-3x when evaulated with -3 give you the value of 3
Evaluated with -3 means that x = -3.
(f-3) = (-3)</span>² - 3 * (-3) = 9 + 9 = 18
18 ≠ 3, so, this is not correct.
3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span> Evaluated with -3 means that x = -3.
f(-3) = (-3)² + 2 * (-3) = 9 - 6 = 3
3 = 3, so this is correct.
4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
Evaluated with 3 means that x = 3.
f(3) = (3)² - 3 * 3 = 9 - 9 = 0
0 ≠ 3, so this is not correct.
The characteristic solution follows from solving the characteristic equation,

so that

A guess for the particular solution may be

, but this is already contained within the characteristic solution. We require a set of linearly independent solutions, so we can look to

which has second derivative

Substituting into the ODE, you have



Therefore the particular solution is

Note that you could have made a more precise guess of

but, of course, any solution of the form

is already accounted for within

.
Answer:
B and D I dont have time to explain
I am sorry.
Thanks for question