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Naddika [18.5K]
3 years ago
14

If anyone knows how to do science ​

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

im using my own knowledge hopefully this is helpful

Orion

milky way

life

earth

years

G2V (I'm not sure with this one)

earths

Step-by-step explanation:

You might be interested in
A positive integer is 1010 more than 2727 times another. their product is 1211712117. find the two integers.
Goshia [24]
1010 + 2727x = y
x*y = 1211712117
x*(1010 + 2727x) = 1211712117
2727x^2 + 1010x - 1211712117 = 0

Here's the nasty part.
In order for this to work, the square root of the quadratic formula must come back with an integer. In fact sqrt (b^2 - 4ac) comes back with
3635568.29 something. which is not a whole number. Either there is an error in the givens or something, but this question is never going to do what you think it will do.
4 0
3 years ago
I need help asap pllz help !!​
swat32

Answer:

14/28

Step-by-step explanation:

14/28 reduces down to 1/2

6 0
3 years ago
What is not a pair of equivalent fractions for 5/8 and 1/2
n200080 [17]
Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.<span>
5/6: 10/12 OR 15/18 
15/30: 5/10 OR 1/2 
45/60: 8/12 OR 4/6 

Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number. 

5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8. 
2/5 and 1/2: 2/5 and 2.5/5 
9/9 and 5/7: 9/9 and ~5.7/9 

Rewrite each in simple form: Find greatest common factor and divide. 

9/54: 1/6 
20/40: 1/2 
100/110: 10/11 

Are these fractions equivalent? 
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole. 


In what situation can you use multiplication to find equivalent fractions? 
I'm sorry but I do not understand this question. 
</span>Source(s):<span>I hope I  helped, seeing as I have graduated with a math degree.</span>
7 0
3 years ago
Help ASAP
polet [3.4K]

Answer:

a and c

Step-by-step explanation:

3 0
3 years ago
2r^2+3s^3-r^2+4t^2-r^2 if r=-2, s=-3, and t=5
dimulka [17.4K]
2(-2)^2+3(-3)^3-(-2)^2+4(5)^2-(-2)^2 = 19

19 is the answer.
3 0
3 years ago
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