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ddd [48]
3 years ago
8

Can someone help me????​

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

Answer:

                       

Step-by-step explanation:

You might be interested in
the perimeter of a rectangle swimming pool is 486 feet. The width of the pool is 35 feet less than the length. Find the length a
statuscvo [17]

Answer:

Length: 139 feet

Width: 104 feet

Step-by-step explanation:

The formula for the perimeter of a rectangle can be given by P = 2l + 2w. We are given the perimeter of the pool along with the width.

P = 486

w = l - 35

From here, all we have to do is plug back into the original formula:

486 = 2l + 2(l - 35)

Which can be further simplified as:

486 = 2l + 2l - 70

486 = 4l - 70

From here, all we have to do is add 70 to both sides of the equation and divide by four:

556 = 4l

139 = l

To make sure that this answer is accurate, we can find that the width of the rectangle should then be 104 (given by 139 - 35). All we have to do is plug back into the original equation:

P = 2l + 2w

P = 2(139) + 2(104)

P = 278 + 208

P = 486

And the substitution works, so the length of the rectangle would be 139 feet and the width would be 104 feet.

5 0
3 years ago
Read 2 more answers
The data set shows the numbers of yogurt pretzels in various bags.
Marizza181 [45]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP FOR TEST will mark brainiest !!
sdas [7]

Answer:

552.920307 yd^2 or 552.92 yd^2 for sigfigs

Step-by-step explanation:

basically you take the area of the entire circle and subtract the interior circle to leave the ring and that’s your answer

so the area formula of a circle is π r^2

the radius (r) is just half the diameter so the entire diameter is 48 so the radius is 24 - π(24)^2 = 1809.557368^2

then the interior circle’s diameter is 40 so the radius is 20 - π(20)^2 = 1256.637061^2

so now it’s just subtraction:

1809.557368 yd^2 - 1256.637061 yd^2 =
552.920307 yd^2 or 552.92 yd^2 for sigfigs

hope this helps :)

6 0
2 years ago
Read 2 more answers
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
yuradex [85]

Answer:

0 < t < 5 is the required interval for the differential equation (t - 5)y' + (ln t)y = 6t to have a solution.

Step-by-step explanation:

Given the differential equation

(t - 5)y' + (ln t)y = 6t

and the condition y(1) = 6

We can rewrite the differential equation by dividing it by (t - 5) as

y' + [(ln t)/(t - 5)]y = 6t/(t - 5)

(ln t)/(t - 5) is continuous on the interval (0, 5) and (5, +infinity).

6t/(t - 5) is continuous on (-infinity, 5) and (5, +infinity)

We see that for these expressions, we have continuity at the intervals (0, 5) and (5, +infinity).

But the initial condition is y = 6, when t = 1.

The solution to differential equation is certain to exist at (0, 5)

Which implies that

0 < t < 5

is the required interval.

3 0
4 years ago
What are the solutions to the quadratics equation 2x+ + 6x – 20 = 1
kodGreya [7K]
Math I hate math bc it sucks
3 0
3 years ago
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