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Citrus2011 [14]
3 years ago
8

What reason does Frederick Lugard use to justify British imperialism?

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0

Answer:

A. Britain will be celebrated for its efforts to improve foreign societies.

Hope this helps :))

USPshnik [31]3 years ago
5 0
His opinion was that christianity needed to be spread

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If we solve h(x) = 36, one of the possible values of x is 1
Mademuasel [1]

Answer:

Step-by-step explanation:

(x+5)² = 36

x+ 5 = ±√36 = ±6

x = -5 ±6 = 1, -11

4 0
3 years ago
(02.06)How many pounds are there in 2 and 3 over 4 tons? (1 ton = 2000 pounds)​
Veseljchak [2.6K]

Answer:

5500 pounds

Step-by-step explanation:

if you mean 2¾

in 2 tons there's 4000 pounds

in ¾ of a ton there is 1500 pounds

4000 + 1500 = 5500 pounds

3 0
2 years ago
A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit
aliina [53]

Answer: All possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

2x+9y=101

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

7 0
3 years ago
The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
Solve 2 2 2 + + (22 − 2) = 0, ≠ 0, ≥ 0
TiliK225 [7]

Answer:

26

Step-by-step explanation:

add 222 and 20

3 0
3 years ago
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