Question

The volume of a gas is 2250 mL at 290 kPa what will the volume be when the pressure is reduced to .9 atm

Answer 1

Answer:

7178.22 mL

Explanation:

Applying,

PV = P'V'................. Equation 1

Where P = Initial pressureof gas, V = Initial volume of gas, P' = Final pressure of gas, V' = Final volume of gas.

make V' the subject of the equation

V' = PV/P'.............. Equation 2

From the question,

Given: V = 2250 mL, P = 290 kPa, P' = 0.9 atm = (101×0.9) = 90.9 kPa

Substitute these values into equation 2

V' = (2250×290)/90.9

V' = 7178.22 mL