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melomori [17]
3 years ago
9

How might you separate a mixture of sand and salt?

Chemistry
1 answer:
sineoko [7]3 years ago
3 0
You can separate a mixture of salt and sand by...

First combing the mixture with water and mix thoroughly until the salt dissolves..

Then you could let the sand settle at the bottom of the salt water, so you can strain salt water to separate the sand from salt water...

To get salt... you would heat up the water to let it evaporate. When all the water is evaporated, the salt will be left behind
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Give an example of chemical equilibrium you have come across into your day-to-day life. Explain how it meets the definition of e
Roman55 [17]
There are many examples of chemical equilibrium all around you. One example is a bottle of fizzy cooldrink. In the bottle there is carbon dioxide (CO2) dissolved in the liquid. There is also CO2 gas in the space between the liquid and the cap
7 0
2 years ago
Describe the motions of particles in the 3 common states of matter
kodGreya [7K]
3 Common States of Matter:

1. Solid - particles are motionless and stick together very closely.

2. Liquid - particles are moving slowly without pattern.

3. Gas - Particles are moving rapidly again without pattern.
3 0
3 years ago
Do all titrations of a strong base with a strong acid have the same ph at the equivalence point?
Luba_88 [7]

Answer:

  • <u>Yes,</u> <em>all titrations of a strong base with a strong acid have the same pH at the equivalence point.</em>

       This <u>pH is 7.</u>

Explanation:

<em>Strong acids</em> and <em>strong bases</em> ionize completely in aqueous solutions. The ionization of strong acids produce hydronium ions, H₃O⁺, and the ionization of strong bases produce hydroxide ions, OH⁻.

Since the ionization of strong acids and bases progress until completion, there is not reverse reaction.

The definition of pH is pH = - log [H₃O⁺]. Acids have low pH (below 7, and greater than 0) and bases have high pH (above 7 and less than 14). Neutral solutions have pH = 7.

Acid-base titrations are a method to determine the concentration of an acid from the known concentration of a base, or the concentraion of a base from the known concentration of an acid.

The<em> equivalence point</em> of the titration is the point at which the the number of moles of hydronium ions and hydroxide ions are equal.

Then, at that point, the hydronium and hydroxide ions will be in the stoichiometric proportion to form a neutral solution, i.e. the pH of the solution wiill be 7.

7 0
3 years ago
An unbalanced equation is shown. In this reaction, 200.0 g of FeS2 is burned in 100.0 g of oxygen, and 55.00 g of Fe2O3 is produ
Crazy boy [7]
<span>4FeS2 + 11O2 = 2Fe2O3 + 8SO2</span>

Percent yield is calculated as the actual yield divided by the theoretical yield multiplied by 100.

Actual yield = 55 g ( 1 mol / 159.69 g ) = 0.34 mol Fe2O3

To find for the theoretical yield, we first determine the limiting reactant.

100 g O2 ( 1 mol / 32 g) = 3.13 mol O2
200 g FeS2 (1 mol / 119.98g) = 1.67 mol FeS2

Therefore, the limiting reactant is O2.

Theoretical yield = 3.13 mol O2 ( 2 mol Fe2O3 / 11 mol O2 ) = 0.57 mol Fe2O3

Percent yield = (0.34 mol / 0.57 mol) x 100 = 59.74%
3 0
3 years ago
The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibri
Nimfa-mama [501]

Answer: The expression for equilibrium constant is \frac{[NH_3]^2}{[H_2]^3[N_2]}

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as k_c

For a general reaction:

aA+bB\rightleftharpoons cC+dD

The equilibrium constant is written as:

k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

Chemical reaction for the formation of ammonia is:

N_2+3H_3\rightleftharpoons 2NH_3

k_c=1.6\times 10^2

Expression for k_c is:

k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}

1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}

8 0
3 years ago
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