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3 years ago

An item is regularly priced at $70. Keiko bought it on sale for 80% off the regular price. How much did Keiko pay? $

Mathematics

2 answers:

pantera1 [17]3 years ago

8 0

Answer:

$14

Step-by-step explanation:

80% of $70 is $14, saving him $56

8090 [49]3 years ago

5 0

The other person has a great answer. Here's another approach.

If the discount is 80%, then you have to pay the remaining 20% (the two percentages add to 100%)

20% of 70 = 0.20*70 = 14

The sale price is $14 which is the amount Keiko pays

We see that Keiko saves 70-14 = 56 dollars.

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10. Which expression is equivalent to 1.6x-4.8?

densk [106]

Answer is

0.8(2x-6)

Step-by-step explanation:

0.8x2x=1.6x

0.8x-6 = -4.8

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3 years ago

Two fields at a state park are 1,000 maters from each other. On a map, the two fields are 8 centimeters apart. what scale is the

marshall27 [118]

Answer:

$\frac{1cm}{125 meters}$

Step-by-step explanation:

To find the scale, we write a ratio of $\frac{map}{real world}$ and simplify.

We know $\frac{map}{real world}=\frac{8cm}{1000 meters}$ .

We simplify to $\frac{1cm}{125 meters}$

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3 years ago

2y - 4x = 4 Rewrite:

USPshnik [31]

Answer:

y - 2x = 2

Step-by-step explanation:

2y - 4x = 4

2(y - 2x) = 4 | : 2

y - 2x = 2

6 0

3 years ago

Read 2 more answers

A(c−b)=d solve for c

Rainbow [258]

Answer:

The solution to this equation could not be determined.

Step-by-step explanation:

Simplifying

a(c + -1b) = d

Reorder the terms:

a(-1b + c) = d

(-1b * a + c * a) = d

(-1ab + ac) = d

Solving

-1ab + ac = d

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Combine like terms: d + -1d = 0

-1ab + ac + -1d = 0

The solution to this equation could not be determined.

4 0

3 years ago

A population of 50 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain up to 500 deer.

rewona [7]

Answer:

p1 = 70 deer

p2 = 98 deer

Step-by-step explanation:

We use the population growth expression:

$N(t)=N_0\,(1+r)^t$

which in our case renders:

$N(t)=N_0\,(1+r)^t\\N(t)=50\,(1+0.4) ^t\\N(t)=50\,(1.4) ^t$

Therefore, after 1 year the population would be:

$N(1)=50\,(1.4) ^1=70$

giving a total of 70 deer

and after two years, it would be:

$N(2)=50\,(1.4) ^2=98$

8 0

3 years ago