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Zolol [24]
3 years ago
15

A fish swims over the waterfall. The distance y (in feet) that the fish falls is given by the function y=16t2 , where t is the t

ime (in seconds).
Mathematics
1 answer:
inessss [21]3 years ago
8 0

Answer:

See Explanation

Step-by-step explanation:

Given

y = 16t^2

The equation is incomplete. However, a possible question could be to calculate the distance of the fish at a particular time

e.g. Time, t = 4,

The distance is:

y = 16t^2

y = 16 * 4^2

y = 16 * 16

y = 256ft

Another possible question is to determine the time taken to cover a certain distance

e.g.

Distance, y = 400

This gives:

y = 16t^2

400 = 16t^2

Divide by 16

25 = t^2

Take square roots

5 = t

t = 5\ seconds

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When you think about it ... massage it and roll it around in your
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First lap:
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Second lap:
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       (100 - 6) = 94
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Third lap:
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These are the lengths of each strip.  They're 2-ft wide, so the area
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I expected to be able to see a pattern developing, but my brain cells
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lap, then add up all the areas and see how close he is:

Fourth lap:
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all the time, so each lap contributes less area than the last one did.

Hey ! Maybe that's the key to the approximate pattern !

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and a 2-ft strip along the width ... twice.  (Approximately.)  So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
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So now we have rectangles measuring

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and the areas of their rectangular strips are
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==> I see that the areas are decreasing by 32-ft² each lap.
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