What is answer???.........easy....???

Mathematics

2 answers:

krek1111 [17]3 years ago

5 0

Answer:

göt kafa frenki ............

Step-by-step explanation:

juin [17]3 years ago

3 0

Answer:

göt kafa frenki ............

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Write an equation, in the slope intercept form, of the line with an x-intercept at (3 , 0) and a y-intercept at (0 , -5).

mamaluj [8]

Hello : let A(3,0) B(0,-5)
the slope is : (YB - YA)/(XB -XA)
(-5-0)/(0-3) = 5/3

an equation, in the slope intercept form is : y - (-5) = (5/3)(x-0)
y = (5/3)x - 5

6 0

3 years ago

What is the slope of the line that passes through the points (2, 1)(2,1) and (17, -17) ?(17,−17)? Write your answer in simplest

Yuliya22 [10]

Answer:

1 + +17 18

______ = ___ = m

2 + -17 -15

7 0

2 years ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$