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nekit [7.7K]
3 years ago
6

Complete the square in order to solve the following quadratic equation: x^2 + 6x = −2

Mathematics
1 answer:
pentagon [3]3 years ago
7 0
To complete square one is basically doing
a
2
+
2
a
b
+
b
2
=
(
a
+
b
)
2

or
a
2
−
2
a
b
+
b
2
=
(
a
−
b
)
2
We can see that
x
2
=
a
2
and
2
a
b
=
6
x
So all we need to condense this into
(
a
+
b
)
2
is a
b
2
term
We know that
2
b
=
6
as
x
=
a

so
b
=
3

and
b
2
=
9
So if we put the
b
2
term in we get
x
2
+
6
x
+
9
−
9
=
(
x
+
3
)
2
−
9
We include the
±
9
because we have to net add nothing to the equation so
9
−
9
=
0
so we really haven't added anything
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The correct option is B): "<span>Let x = 1st integer. Let x + 2 = 2nd integer.</span><span>"
Given that "The sum of two consecutive odd integers is 28."
 
Now the difference between two odd numbers is 2. So this means that one odd number has to be greater than the other by 2.

Let the smaller number be 'X' therefore the bigger number will be 'x+2' thus x + (x+2) = 28
 
therefore, x + x + 2 = 28 now we subtract "2" from both the sides
therefore, 2x = 26 now dividing throughout by 2 we get:

x = 13 therefore, x + 2 = 13+2
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therefore, the numbers are 13 AND 15</span>
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Answer:

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The answer is true...
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Solve 3 ^ x + 6 = 3 ^ 4
aleksklad [387]

Answer:

3.93 (approx.)

Step-by-step explanation:

3 ^ x + 6 = 3 ^ 4 can be rewritten as 3 ^ x  = 3 ^ 4  -   6, or

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Then 3^x = 75, or

x*ln 3 = ln 75

Solving for x:  

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8 0
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Answer:

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