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marishachu [46]
3 years ago
6

3X-4 over 14 equals 9 over 10 solve for x

Mathematics
1 answer:
Maru [420]3 years ago
8 0

Answer:

3x-4/14=9/10

You change the subtraction to addition

3x+4/14=9/10

Then you change the fractions to decimals

Step-by-step explanation:

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Umm y = 2× + 8 ? Hard
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A survey reveals that the sales of smartphones is increasing considerably. The average annual sales of smartphones, in million u
padilas [110]

Answer:

C. When the survey was initially conducted average sales of smartphones was 1.7 millions units.

Step-by-step explanation:

We have been given that the average annual sales of smartphones, in million units, n years after the survey is conducted is modeled by function p(n)=1.7\cdot b^n, where the parameter b is an unknown positive base.


We are asked to find the true statement about our given function.

A. If b= 1.45, the annual growth rate of the sales of smartphones is 145%.

Since we know that b equals (1+r) for growth function, where r is in decimal form.

If b=1.45, it means that the annual growth rate will be 45% as 0.45 is decimal form of 45%, therefore, statement A is not true.

B.  If b= 1.02, annual sales of smartphones will double in 2 years.

If b=1.02, it means that the annual growth rate will be 2% as 0.02 is decimal form of 2%, therefore, statement B is not true.

C. When the survey was initially conducted average sales of smartphones was 1.7 millions units.

Since we know that an exponential function is in form y=a*b^x, where a in initial value of function. We can see from our given function that a equals 1.7, therefore option C is a true statement.

D. The average sales of smartphones increases by 1.7 millions units every year.

Since our function is not a linear function, instead it is an exponential function, so rate of change can not be constant.

Therefore, option D is not true regarding our given function.

7 0
3 years ago
I’ll give you the BRAINLYEST answer if you can help me on this question!
igomit [66]

Answer:

i think its 6

Step-by-step explanation:

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The product of 5 and m squared,increased by the sum of the square of m and 5
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The product (multiplication) of 5 and m squared (²) increased (addition) by the sum (addition) of the square (²) of m and 5.

(5m²) + (m² + 5)
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Name/ Uid:1. In this problem, try to write the equations of the given surface in the specified coordinates.(a) Write an equation
Gemiola [76]

To find:

(a) Equation for the sphere of radius 5 centered at the origin in cylindrical coordinates

(b) Equation for a cylinder of radius 1 centered at the origin and running parallel to the z-axis in spherical coordinates

Solution:

(a) The equation of a sphere with center at (a, b, c) & having a radius 'p' is given in cartesian coordinates as:

(x-a)^{2}+(y-b)^{2}+(z-c)^{2}=p^{2}

Here, it is given that the center of the sphere is at origin, i.e., at (0,0,0) & radius of the sphere is 5. That is, here we have,

a=b=c=0,p=5

That is, the equation of the sphere in cartesian coordinates is,

(x-0)^{2}+(y-0)^{2}+(z-0)^{2}=5^{2}

\Rightarrow x^{2}+y^{2}+z^{2}=25

Now, the cylindrical coordinate system is represented by (r, \theta,z)

The relation between cartesian and cylindrical coordinates is given by,

x=rcos\theta,y=rsin\theta,z=z

r^{2}=x^{2}+y^{2},tan\theta=\frac{y}{x},z=z

Thus, the obtained equation of the sphere in cartesian coordinates can be rewritten in cylindrical coordinates as,

r^{2}+z^{2}=25

This is the required equation of the given sphere in cylindrical coordinates.

(b) A cylinder is defined by the circle that gives the top and bottom faces or alternatively, the cross section, & it's axis. A cylinder running parallel to the z-axis has an axis that is parallel to the z-axis. The equation of such a cylinder is given by the equation of the circle of cross-section with the assumption that a point in 3 dimension lying on the cylinder has 'x' & 'y' values satisfying the equation of the circle & that 'z' can be any value.

That is, in cartesian coordinates, the equation of a cylinder running parallel to the z-axis having radius 'p' with center at (a, b) is given by,

(x-a)^{2}+(y-b)^{2}=p^{2}

Here, it is given that the center is at origin & radius is 1. That is, here, we have, a=b=0,p=1. Then the equation of the cylinder in cartesian coordinates is,

x^{2}+y^{2}=1

Now, the spherical coordinate system is represented by (\rho,\theta,\phi)

The relation between cartesian and spherical coordinates is given by,

x=\rho sin\phi cos\theta,y=\rho sin\phi sin\theta, z= \rho cos\phi

Thus, the equation of the cylinder can be rewritten in spherical coordinates as,

(\rho sin\phi cos\theta)^{2}+(\rho sin\phi sin\theta)^{2}=1

\Rightarrow \rho^{2} sin^{2}\phi cos^{2}\theta+\rho^{2} sin^{2}\phi sin^{2}\theta=1

\Rightarrow \rho^{2} sin^{2}\phi (cos^{2}\theta+sin^{2}\theta)=1

\Rightarrow \rho^{2} sin^{2}\phi=1 (As sin^{2}\theta+cos^{2}\theta=1)

Note that \rho represents the distance of a point from the origin, which is always positive. \phi represents the angle made by the line segment joining the point with z-axis. The range of \phi is given as 0\leq \phi\leq \pi. We know that in this range the sine function is positive. Thus, we can say that sin\phi is always positive.

Thus, we can square root both sides and only consider the positive root as,

\Rightarrow \rho sin\phi=1

This is the required equation of the cylinder in spherical coordinates.

Final answer:

(a) The equation of the given sphere in cylindrical coordinates is r^{2}+z^{2}=25

(b) The equation of the given cylinder in spherical coordinates is \rho sin\phi=1

7 0
2 years ago
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