There are two of them.
I don't know a mechanical way to 'solve' for them.
One can be found by trial and error:
x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
<em>x=4</em> . . . . . 2^4 = <em><u>16</u></em> . . . . 4(4) = <em><u>16</u></em> . . . . Yes ! That works ! yay !
For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.
The point is near, but not exactly, <em>x = 0.30990693...
</em>If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks.<em> </em> If anybody out there has it, I'm
waiting with all ears.<em>
</em>
The numbers in this problem are ordered pairs, which are points on a graph.
These are (10, 20), (-10, 20), (-10, -10), and (10, -10).
To find the area and perimeter of this shape, you must first find the distance between each point.
Distance between (10, 20) and (-10, 20):
Since the y-value remains the same here, we just have to find the difference in x-values.
This means 10 - (-10)
A negative being subtracted is the same as a positive being added.
That means 10 - (-10) is the same as 10 + 10.
10 + 10 = 20, so the distance between (10, 20) and (-10, 20) is 20 units.
Distance between (-10, 20) and (-10, -10):
The x-values are the same here so just find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between the (-10, 20) and (-10, -10) is 30 units.
Distance between (-10, -10) and (10, -10):
The y-values are the same so just find the difference between the x-values.
10 - (-10) = 10 + 10 = 20
The distance between (-10, -10) and (10, -10) is 20 units.
Distance between (10, -10) and (10, 20):
The x-values are the same so find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between (10, -10) and (10, 20) is 30 units.
So now we know the side lengths of the room are 20 units, 30 units, 20 units, and 30 units.
To find the perimeter, add all the side lengths together.
20 + 30 + 20 + 30 = 100
The perimeter of the room is 100 units.
To find the area, multiply the length by the width.
The length is 20 units and the width is 30 units.
20 • 30 = 600
The area of the room is 600 units.
Final answers:
Perimeter = 100
Area = 600
Hope this helps!
5/8
6/3
7/10
These are all the answers 4/8 is 1/2 and 5/8 is over it there is no half of 3 but 6/3 is 2 and 2 is a whole number it's over 1/2
5/10=1/2 and 7/10 is over it 1/4 isn't an answer because 2/4=1/2 6/12=1/2 but it says over 1/2 and finally 5/12 isn't it because like I said above 6/12 is 1/2
Answer:
Step-by-step explanation:
i want to help you but what do you need help with??
Answer:
Part 1) 
Part 2) 
Part 3) 
Part 4) 
Part 5) 
Step-by-step explanation:
Part 1) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem
Part 2) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem
Part 3) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem
substitute the values
Part 4) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem
Part 5) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem
