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ddd [48]
3 years ago
5

NO LINKS I WILL REPORT!! but help plsss What is the value of y? 2yº y + 10° 50°

Mathematics
1 answer:
liq [111]3 years ago
7 0

Answer:

y=40

I hope it's helps you

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I just took the test the answer is 9 cm.
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The distance between major cracks in a highway follows an exponential distribution with a mean of four miles. (a) what is the st
Lesechka [4]
For an exponential distribution, the standard deviation is equal to the mean.

(a) the standard deviation is 4 miles.
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3 years ago
An investment of 11,000 is made into an account that earns 4.25% annual compound interest for 30 months. Assuming no other depos
LenKa [72]

Answer:

It should be $12168.75

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 4.25%/100 = 0.0425 per year,

then, solving our equation

I = 11000 × 0.0425 × 2.5 = 1168.75

I = $ 1,168.75

The simple interest accumulated

on a principal of $ 11,000.00

at a rate of 4.25% per year

for 2.5 years is $ 1,168.75.

1,168.75 + 11000 = 12168.75

5 0
3 years ago
Slope = -2/5, contains the point (10,3)
Daniel [21]

Answer: if this is supposed to be in slope-intercept form

the equation would be: y = -2/5x + 7

Step-by-step explanation:

so the slope is: -2/5 and the point is (10,3) considering that x = 10 and y = 3

so we would plug this information into this equation: y = mx + b (slope-intercept form)

3 = -2/5(10) + b

3 = -4 + b

b = 7

and if we plug this in:

y = -2/5x + 7

5 0
3 years ago
use the intermediate value theorem to determine whether the following equation has a solution or not x^3-3x-1
xxTIMURxx [149]

Answer:

Yes, this equation has a solution. According to Intermediate Value Theorem at least one solution for [0,2]

Step-by-step explanation:

Hi there!

1) Remember a definition.

Intermediate Value Theorem:

If f is continuous on a given closed interval [a,b], and f(a)≠f(b) and f(a)<k<f(b) then there has to be at least one number 'c' between 'a' and 'b', such that f(c)=k

----

(Check the first graph as an example)

2) The Intermediate Value Theorem can be applied to determine whether there is a solution on a given interval.

Let's choose the interval [0,2]

f(x)=x^{3}-3x-1\\f(0)=(0)^{3}-3(0)-1\\f(0)=-1\\f(0)

Proceed to the other point: 2

f(x)=x^{3}-3x-1\\f(2)=(2)^{3}-3(2)-1\\f(2)=1\\f(2)>0\\

3) Check the 2nd Graph for a the Visual answer, of it.  And the 3rd graph for all solutions of this equation.

3 0
3 years ago
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