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irga5000 [103]
3 years ago
14

Which is the equation of a line with the same y-intercept as the line with the equation 5x -4y =12!

Mathematics
1 answer:
Lynna [10]3 years ago
7 0

Answer: the answer is d

Step-by-step explanation:

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Please help me understand how to do this and the answer!
Murrr4er [49]
Turn F(x) into vertex form:

y=x^2+8x+6
y-6=x^2+8x
y-6+16=x^2+8x+16
y+10=(x+4)^2
Thus the vertex is (-4,-10)

This is a minimum because the parabola is up up, or is positive
6 0
3 years ago
Solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 + 3x = 24
Sophie [7]
We have that
x²<span> + 3x = 24
</span><span>Group terms that contain the same variable
</span>(x² + 3x) = 24
<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x² + 3x+2.25) = 24+2.25

Rewrite as perfect squares

(x+1.5)² = 26.25
(+/-)[x+1.5]=5.12
(+)[x+1.5]=5.12----> x=5.12-1.5--->  x=3.62
(-)[x+1.5]=5.12-----> x=-1.5-5.12---> x=-6.62

the answer is
<span>3.62, –6.62</span>
5 0
3 years ago
Graph a parabola whose x-intercepts are at x=-3 and x=5 and whose minimum value is y=-4
docker41 [41]

Answer:

(See explanation for further details)

Step-by-step explanation:

The standard equation of the parabola is:

y + 4 = C \cdot (x-k)^{2}

The formula is now expanded into a the form of a second-order polynomial:

y + 4 = C\cdot x^{2} -2\cdot C\cdot k \cdot x +C\cdot k^{2}

y = C\cdot x^{2} - (2\cdot C \cdot k) \cdot x + (C\cdot k^{2}-4)

The general equation of the second-order polynomial is:

x = \frac{2\cdot C \cdot k \pm \sqrt{4\cdot C^{2}\cdot k^{2}-4\cdot C\cdot (C\cdot k^{2}-4)}}{2\cdot C}

x = k \pm \frac{\sqrt{C^{2}\cdot k^{2}-C^{2}\cdot k^{2}+4\cdot C}}{C}

x = k \pm 2\cdot \frac{\sqrt{C}}{C}

x = k \pm \frac{2}{\sqrt{C}}

The equations to be solved are presented herein:

-3 = k -\frac{2}{\sqrt{C}}

5 = k + \frac{2}{\sqrt{C}}

Now, the solution of the system is:

-3 +\frac{2}{\sqrt{C}} = 5 -\frac{2}{\sqrt{C}}

\frac{4}{\sqrt{C}} = 8

\sqrt{C} = \frac{1}{2}

C = \frac{1}{4}

k = 5 - \frac{2}{\sqrt{\frac{1}{4} }}

k = 1

The equation of the parabola is:

y = \frac{1}{4}\cdot (x-1)^{2} -4

Lastly, the graphic of the function is included as attachment.

3 0
3 years ago
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