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klemol [59]
2 years ago
5

Maria has a bag with 6 red marbles , 6 blue marbles , and 4 green marbles . Without looking Maria pick one marble. She does not

replace it , and she picks another one. On the first pick , Maria gets a green marble. What is the probability that she gets a red marble on her second pick ?
Mathematics
1 answer:
podryga [215]2 years ago
7 0
40%

The probability of her getting a red marble is the number of red marbles divided by the number of total marbles. Since she picked a green marble first, we must subtract one marble from the total number of marbles, so that the total # of marbles is 6 + 6 + 4 = 16 - 1 (green marble) = 15. Since there are 6 red marbles, our probability is 6/15 or 2/5. Converted to percentage form, this is 0.4 —> 40%
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Step-by-step explanation:

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On each of three pieces of paper a three digit number is written two of the digits are covered . The sum is 826. What is the sum
Ket [755]

Answer:

9

Step-by-step explanation:

The diagram showing the three pieces of paper of three digit in which two of the letters were covered can be seen below.

From the diagram; we have;

243 , 1_7 , _26

Assuming the covered digits are _

The sum is 826.

i.e

243 + 1_7 + _26 = 826

The objective is to determine the sum of the two unknown digits

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From ; 1_7 , we have the choice to pick from 0 - 9

Assuming the covered digit is 0; let's check if we are right

So; 243 + 1<u>0</u>7  +  _26 = 826

350 +   _26 = 826

_26 = 826 - 350

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So; the covered digit is in the position of 4 , but it doesn't tally together

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Let consider the covered digit to be 5 for example.

So; 243 + 1<u>5</u>7  +  _26 = 826

400 +   _26 = 826

_26 = 826 - 400

_26 =  426

The covered digit is in the position of 4

SO;

<u>4</u>26 = 426

Here , our assumption is right.

As such , the covered digits are 5 and 4

The sum of the two  covered digits are = 5 + 4 = 9

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2 years ago
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musickatia [10]

9514 1404 393

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Step-by-step explanation:

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Answer:

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