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vitfil [10]
3 years ago
9

A rational number can be written as the ratio of one _______ to another and can be represented by a repeating or terminating dec

imal
Fill in the blanks
Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0
A rational number can be written as the ratio of one integer to another and can be represented by a repeating or terminating decimal.
Allisa [31]3 years ago
7 0

Answer:

A rational number can be written as the ratio of one "<em>integer</em> " to another and can be represented by a repeating or terminating decimal.

Step-by-step explanation:

Consider the provided information.

Now consider the definition of rational number.

Rational number: A number is said to be rational, if it is in the form of p/q. Where p and q are integer and denominator is not equal to 0 and can be represented by a repeating or terminating decimal.

For example:

22/3=7.333333

55/1=55

44/8=5.5

Thus the blank should be filled by "Integer".

A rational number can be written as the ratio of one "<em>integer"</em> to another and can be represented by a repeating or terminating decimal.

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In an arbitrary triangle can be only one obtuse angle, and the side which lies opposite to the largest angle is the largest. Then since <span>angle \theta is opposite the side of length a</span>  you can conclude that a>c and a>b.



6 0
3 years ago
What is the value of -9 1/5 - 10 + 2/5 + 2(14 1/2 - 7)?​
Art [367]

Answer:

-9 1/5 - 10 + 2/5 + 2(14 1/2 - 7) = -3.8

Step-by-step explanation:

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3 years ago
For qualitative data, the relative frequency for a class is computed as
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D. Class frequency divided by the total frequency.

4 0
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126-pizza

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Step-by-step explanation:

4 0
3 years ago
Given the recursive function f(n) = f(n - 1) - 3 ; f(1) = 9 , what would be the first three terms of the sequence ?
Ann [662]

The first three terms of sequence are 9 , 6 , 3

<em><u>Solution:</u></em>

Given the recursive function f(n) = f(n - 1) - 3

Where f(1) = 9

To find: First three terms of sequence

Substitute n = 2 , n = 3 and n = 4 in given recursive function

When n = 2

f(n) = f(n - 1) - 3

f(2) = f(2 - 1) - 3

f(2) = f(1) - 3

f(2) = 9 - 3 = 6

f(2) = 6

Thus second term is 6

When n = 3

f(3) = f( 3 - 1) - 3

f(3) = f(2) - 3

f(3) = 6 - 3 = 3

f(3) = 3

Thus the third term is 3

When n = 4

f(4) = f( 4 - 1) - 3

f(4) = f(3) - 3

f(4) = 3 - 3

f(4) = 0

Thus the fourth term is 0

Thus first three terms of sequence are 9 , 6 , 3

6 0
3 years ago
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