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Scrat [10]
3 years ago
7

3 1/2+ 4 5/6 in simpleast form

Mathematics
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer:

23 is the answer.

hope it will help u

zhenek [66]3 years ago
7 0

Answer:

3/4 I believe

Step-by-step explanation:

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Nani!? Omae wa mou shindeiru
3 0
3 years ago
Read 2 more answers
Which function has a domain​
Novosadov [1.4K]

Answer:

F(x) = - \sqrt[3]{x}  

Step-by-step explanation:

A square root can only have a positive input for the domain

(The domain is the input for the function)

The cube root can be either negative or positive as an input

F(x) = - \sqrt[3]{x}  can have inputs from negative infinity to infinity

5 0
2 years ago
What fraction is equivalent to 4/3
Nadya [2.5K]

Answer:

its gon be a mixed number tho: 1 1/3

Step-by-step explanation:

7 0
4 years ago
I do not understand how you can do this without more information.
Nadusha1986 [10]

Answer:

Step-by-step explanation:

I think you are correct. The bottom of the drawing has to have a width or someway of finding it. Also the breakup of the height needs some sort of clue where that breakup occurs.  I think you likely have to ask your instructor.

3 0
3 years ago
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The
sattari [20]

Answer:

C. H0 : p = 0.8 H 1 : p ≠ 0.8

The test is:_____.

c. two-tailed

The test statistic is:______p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

The p-value is:_____. 0.09887

Based on this we:_____.

B. Reject the null hypothesis.

Step-by-step explanation:

We formulate null and alternative hypotheses as  proportion of people who own cats is significantly different than 80%.

H0 : p = 0.8 H 1 : p ≠ 0.8

The alternative hypothesis H1 is that the 80% of the  proportion is different and null hypothesis is , it is same.

For a two tailed test for significance level = 0.2 we have critical value  ± 1.28.

We have alpha equal to 0.2  for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28

The test statistic is

p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

Where p = 0.8 , q = 1-p= 1-0.8= 0.2

n= 200

Putting the values

0.8 ± 1.28 \sqrt{\frac{0.8*0.2}{200} }

0.8 ± 0.03620

0.8362, 0.7638

As the calculated value of z lies within the critical region  we reject the null hypothesis.

8 0
3 years ago
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