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3 years ago

A bond between two iodine atoms would have what as the percent ionic character

Chemistry

2 answers:

Nadusha1986 [10]3 years ago

4 0

I’d guess 83? Braileist?

NISA [10]3 years ago

4 0

Answer:

Your answer should be 53%

I'm very sorry if I'm wrong I have not done this in forever

Explanation:

No explanation

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How many sulfur atoms are present in 25.6 g of Al2(S2O3)3

IgorC [24]

Given the mass of $Al_{2}(S_{2}O_{3})_{3}$ =25.6 g

The molar mass of $Al_{2}(S_{2}O_{3})_{3}$ =390.35g/mol

Converting mass of $Al_{2}(S_{2}O_{3})_{3}$ to moles:

$25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}$

Converting mol $Al_{2}(S_{2}O_{3})_{3}$ to mol S:

$0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS$

Converting mol S to atoms of S using Avogadro's number:

1 mol = $6.022*10^{23}atoms$

$0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms$

5 0

3 years ago

Sound waves are ____ waves

liubo4ka [24]

Answer:

Longitudinal waves

Explanation:

4 0

2 years ago

If 7.50 g of the unknown compound contained 0.250 mol of c and 0.500 mol of h, how many moles of oxygen, o, were in the sample?

Mice21 [21]

It would be 100.60 because we're adding like to the atmosphere it connects to lubricator and then it turns so that's 100.60

3 0

3 years ago

What Is The Difference Between A Monatomic Ion And A Polyatomic Ion What is the difference between a polyatomic ion and a monato

rosijanka [135]

There is one atom in a Monoatomic Ion whereas Many in Polyatomic.

It's simple!!! you're Welcome:)

3 0

4 years ago

suppose that two hydroxides, moh and m′ (oh)2, both have a ksp of 1.39 × 10−12 and that initially both cations are present in a

11Alexandr11 [23.1K]

When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>

Equation :

MOH (s) ⇄ M⁺ (aq) ₊ OH⁻(aq)

K $sp$ = [M⁺] [OH⁻]

K $sp$ = 1.39×10⁻¹² and [M⁺] = 0.001M

∴ 1.39×10⁻¹² = (0.001M) [OH⁻]

[OH⁻] = 1.004×10⁻¹⁹M

pOH = -log [OH⁻] = 11.9

pH = 14 - pOH

= 14 - 11.9

To learn more about solubility equilibrium ;

https://brainly.in/question/9213521

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8 0

2 years ago