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andrey2020 [161]
3 years ago
8

9. The broken appearance of pencil in a glass of water is due

Chemistry
1 answer:
shtirl [24]3 years ago
3 0
Yes it is due to refraction of light in water
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6. (10 Points) The volume of a helium balloon in Los Angeles is 14.0 L The
yan [13]

Answer:

V₂ = 15.27 L

Explanation:

Given data:

Initial volume = 14.0 L

Initial temperature = 25°C (25 + 273.15 = 298.15 k)

Final temperature = 52°C = (52+273.15 = 325.15 k)

Final volume = ?

Solution:

Charles Law:

" The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure "

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 14.0 L × 325.15 K / 298.15 k

V₂ = 4552.1 L.K / 298.15 K

V₂ = 15.27 L

5 0
3 years ago
How do lone pairs of electrons influence the structure of molecules
dybincka [34]

Answer:

Electron pairs repel each other and influence bond angles and molecular shape. The presence of lone pair electrons influences the three-dimensional shape of the molecule.

Explanation:

6 0
3 years ago
In one or two sentences, explain why the combined weight of several liquids mixed in an open flask can be less than but never mo
exis [7]

Answer:

j

Explanation:

h

6 0
3 years ago
Why has Earth's climate changed so rapidly in recent years?
ser-zykov [4K]
I believe it’s C , People are burning too many fossil fuels .
5 0
3 years ago
Perform the following conversions:
ololo11 [35]

Answer:

a) 20^0C and 293K

b) 437K and 327.2^0F

c) -273^0C and 459.44^0F

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like ^0C , ^0Fand K  

These units of temperature are inter convertible.

t^0C=(t+273)K

t^oC=\frac{5}{9}\times (t^oF-32)

K-273=\frac{5}{9}\times (^oF-32)

a)  68°F (a pleasant spring day) to °C and K.

Converting this unit of temperature into ^0C and K by using conversion factor:

t^oC=\frac{5}{9}\times (68^oF-32)

t=20^0C

20^0C=(20+273)K=293K

b) 164°C (the boiling point of methane, the main component of natural gas) to K and °F

Conversion from degree Celsius to Kelvins  and Fahrenheit

164C=\frac{5}{9}\times (t^oF-32)

t^0F=327.2

164°C=(164+273)K=437 K

c) 0K (absolute zero, theoretically the coldest possible temperature) to °C and °F.

K-273=\frac{5}{9}\times (t^oF-32)

0-273=\frac{5}{9}\times (t^oF-32)

t=-459.4^0F

t^K=(0-273)^0C=-273^0C

8 0
3 years ago
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