Question

The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argon sample was 14.2 L what what’s the initial volume of the argon sample? Assume ideal behavior

Answer 1

Answer:

36.09 L

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume.

Since we're finding the initial volume

$V_1 = \frac{P_2V_2}{P_1}$

We have

$V_1 = \frac{7.98 \times 14.2}{3.14} = \frac{113.316}{3.14} \\ = 36.0878...$

We have the final answer as

36.09 L

Hope this helps you