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musickatia [10]
3 years ago
10

The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argo

n sample was 14.2 L what what’s the initial volume of the argon sample? Assume ideal behavior
Chemistry
1 answer:
noname [10]3 years ago
8 0

Answer:

<h2>36.09 L</h2>

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume.

Since we're finding the initial volume

V_1 =  \frac{P_2V_2}{P_1}  \\

We have

V_1 =  \frac{7.98 \times 14.2}{3.14} =   \frac{113.316}{3.14}  \\  = 36.0878...

We have the final answer as

<h3>36.09 L</h3>

Hope this helps you

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Explanation:

First thing's first, we have to write out the balanced chemical equation for the reaction.

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(1 * (14 * 2)) = 28g of N2 reacts with (3 * (1 * 2)) = 6g of H2

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A laboratory analysis of an unknown sample yields 74.0% carbon, 7.4% hydrogen, 8.6% nitrogen, and 10.0% oxygen. What is the empi
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Answer: Mg is the excess reactant for the forward reaction.

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