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faltersainse [42]
3 years ago
8

If AD is an altitude of ABC, then

Mathematics
1 answer:
serg [7]3 years ago
4 0

Answer:

ADB is C. 90 degrees.

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What is the surface area of the solid shown below?
Ugo [173]

Answer:

\text{C. }156\:\mathrm{cm^3}

Step-by-step explanation:

The surface area of the triangular prism consists of three rectangles and two triangles.

Rectangle One - 5 x 12 = 60 cm^2

Rectangle Two - 4 x 12 = 48 cm^2

Rectangle Three - 3 x 12 = 36 cm^2

Triangles - 2 x 1/2 x 3 x 4 = 12 cm^2

Thus, the total surface area of the solid is 60+48+36+12=\boxed{\text{C. }156\:\mathrm{cm^3}}

8 0
3 years ago
First Data Corp. records indicate that in 2005, 43% of adult email users received a phishing email. A phishing email replicates
ra1l [238]

Answer:

P(x) = 45/100 = 0.45

Mean sample distribution = probability x number sampled by the survey.

Mean sample distribution = 0.45 x 800 = 360.00 to two decimal places.

Step-by-step explanation:

Convert the percentage to decimal probability.

45%. P(x) = 45/100 = 0.45

If there are ranges of probability values, we construct a probability distribution table. This is not necessary in the case of one probability value(45%)

Multiply the probability by the number adults to be surveyed on whether they have received phishing emails.

0.45 x 800 = 360.

Here, we assume that the 45% recorded by 2005 data, is still valid for the recent trends.

5 0
3 years ago
Read 2 more answers
Slope of this question please and thank you!!!!! :)))))))))))
fiasKO [112]

Answer:

the slope is 1

Step-by-step explanation:

hope this helps :)

4 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
nikklg [1K]

The answer to this question is option A. 49

5 0
3 years ago
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