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faltersainse [42]
3 years ago
8

If AD is an altitude of ABC, then

Mathematics
1 answer:
serg [7]3 years ago
4 0

Answer:

ADB is C. 90 degrees.

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Jade wants to buy a $200,000 term life insurance policy. She is 34 years old. Using the premium table, what is her annual premiu
AnnZ [28]

Premium rates are usually for  premium per fixed face value. Jade's annual premium for a 10 year policy is given by Option b: $1,202

<h3>How to calculate the total annual premium for $x ?</h3>

If its given that the annual premium is $p per $y face value, then we can calculate the annual premium for $1 face value and then use it to calculate annual premium for $x.

Using proportions, we get:

\rm \$y \: face \: value : \$p \: annual \: premiun\\\\\rm \$1 \: face \: value : \$\dfrac{p}{y} \: annual \: premiun\\\\\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premiun\\

For given case, from the tables, we see that for age 34, and 10 year life insurance for female gender , there is annual premium of 6.01 per $1000 face value.
Thus, we have p = 6.01, y = 1000

Since Jade wants to buy Life insurance for $200,000, thus, x = $200,000

Putting it in the above derived formula, we get:

\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premium\\\\\rm \$200000\:face\: value : \$\dfrac{6.01 \times 200000}{1000} \: annual \: premium\\ = \$1202 \: annual \: premiun

Thus, Jade's annual premium for a 10 year policy is given by Option b: $1,202

Learn more about calculating annual premium cost here:

brainly.com/question/13168988

4 0
3 years ago
During which months in 2005 was Fargos precipitation more than 20 mm below its long term average
nevsk [136]
I will send you a hopefully helpful link. https://www.ncdc.noaa.gov/sotc/national/201403
6 0
3 years ago
Answer this pleaseee !!
photoshop1234 [79]

Answer:

D.

Step-by-step explanation:

m<F = m<B - Corresponding Angles Theorem

m<B + m<A = 180 - Adjacent Angles Theorem

180 - 105 = m<A

75 = m<A; therefore, m<A = 75.

6 0
3 years ago
Read 2 more answers
Find the distance between the points (<br> -<br> 10,12) and (15,12).
Nitella [24]
The distance formula is:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

We are given two points in the form (x,y), so plug in the values to the distance formula:

d= \sqrt{(-10-15)^2-(12-12)^2}

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

d= \sqrt{(-25)^2}

The square and square root cancel each other out leaving us with 25.

The answer is 25.


5 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
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