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Natalija [7]
3 years ago
11

The rectangle is enlarged by a scale factor of 5. What is the new

Mathematics
2 answers:
Kisachek [45]3 years ago
5 0

Answer:

25 I'm pretty sure

Step-by-step explanation:

5×5=25

bazaltina [42]3 years ago
4 0

Answer:

25 cm

Step-by-step explanation:

If it is enlarged by the scale factor of 5, you are multiplying by 5. 5 cm is the longest side, so therefore 5 cm times 5 cm is equal to 25.

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An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment. For this s
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Answer: c. ​10

Step-by-step explanation:

Given : An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment.

For this study, the three sample means are, M1 = 1, M2 = 2, and M3 = 3.

Grand mean = \overline{X}=\dfrac{M1+M2+M3}{3} [All sample have equal elements]

=\dfrac{1+2+3}{3}=2

For ANOVA,

SS_{between}=n\sum(M_i-\overline{X})^2 , where i= 1, 2 , 3

SS_{between}=5((1-2)^2+(2-2)^2+((3-2)^2)

SS_{between}=5((-1)^2+(0)^2+((1)^2)= 5(1+1)=10

Hence,the value would be obtained for SS_{between}=10 .

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8 0
3 years ago
Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of
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Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

n = 120, \pi = \frac{58}{120} = 0.4833

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

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Step-by-step explanation:

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