Please explain this to me and say the answer!! ASAP!!!

docker41 [41]

Simplifying Rs = st + -1Rt Solving sR = st + -1tR Solving for variable 's'. Move all terms containing s to the left, all other terms to the right. Add '-1st' to each side of the equation. sR + -1st = st + -1st + -1tR Combine like terms: st + -1st = 0 sR + -1st = 0 + -1tR sR + -1st = -1tR Combine like terms: -1tR + tR = 0 sR + -1st + tR = 0

8 0

3 years ago

Read 2 more answers

You set up a game where the player throws a dart until they pop a balloon. There are 3 red balloons, 30 green balloons, and 100

Airida [17]

If this is probability then the answer should be $.50 bacause you throw the dart until you hit 1 balloon there is 100 white balloons so there is a .75% chance to hit white, a .02% chance to hit red and a .22% chance to hit green. the most likely one to hit is white. so you would earn
$.50 per game

4 0

4 years ago

Rewrite your expression using the distributive property:5m + 25n

Hunter-Best [27]

Answer:

Step-by-step explanation: 5m+25n

4 0

3 years ago

The number 12 is relatively prime to:_______. a) 6 b) 15 c) 8 d) 25

ra1l [238]

Answer: I think the answer is 15.

3 0

4 years ago

Calculus graph please help

tresset_1 [31]

Answer:

See Below.

Step-by-step explanation:

We are given the graph of y = f'(x) and we want to determine the characteristics of f(x).

Part A)

f is increasing whenever f' is positive and decreasing whenever f' is negative.

Hence, f is increasing for the interval:

$(-\infty, -2) \cup (-1, 1)\cup (3, \infty)$

And f is decreasing for the interval:

$\displaystyle (-2, -1) \cup (1, 3)$

Part B)

f has a relative maximum at x = c if f' turns from positive to negative at c and a relative minimum if f' turns from negative to positive to negative at c.

f' turns from positive to negative at x = -2 and x = 1.

And f' turns from negative to positive at x = -1 and x = 3.

Hence, f has relative maximums at x = -2 and x = 1, and relative minimums at x = -1 and x = 3.

Part C)

f is concave up whenever f'' is positive and concave down whenever f'' is negative.

In other words, f is concave up whenever f' is increasing and concave down whenever f' is decreasing.

Hence, f is concave up for the interval (rounded to the nearest tenths):

$\displaystyle (-1.5 , 0) \cup (2.2, \infty)$

And concave down for the interval:

$\displaystyle (-\infty, -1.5) \cup (0, 2.2)$

Part D)

Points of inflections are where the concavity changes: that is, f'' changes from either positive to negative or negative to positive.

In other words, f has an inflection point wherever f' has an extremum point.

f' has extrema at (approximately) x = -1.5, 0, and 2.2.

Hence, f has inflection points at x = -1.5, 0, and 2.2.

7 0

3 years ago