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NeTakaya
3 years ago
14

Write the fraction 28/21 in its simplest

Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0
28 divided by 7 = 4. 21 divided by 7 = 3. (4/3)

28/21 in simplest form is 4/3.

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How do you work out 8x+3=8×+27
Alekssandra [29.7K]

Answer:

No solution

Step-by-step explanation:

8x + 8 = 8x + 27

You then cancel out the 8s. 8 - 8 = 0

Which leaves you with 8 = 27...

Since this is an untrue statement, the answer would be no solution, unless you typed it wrong.

4 0
3 years ago
Square the following numbers<br> 5, 9, 12​
IRISSAK [1]

Answer:

5² = 25

9² = 81

12² = 144

hope it helps

have a nice day

7 0
3 years ago
Read 2 more answers
Use the equation below to find a, if b = 5 and c = 12<br><br> a = 27 - b - c
vovikov84 [41]

Answer: 10

a=27-5-12=10

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3 years ago
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Real life situation where an estimate makes sense
harina [27]

I'm in a hurry to get home.
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Even better:

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6 0
3 years ago
Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
3 years ago
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