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NeTakaya
3 years ago
14

Write the fraction 28/21 in its simplest

Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0
28 divided by 7 = 4. 21 divided by 7 = 3. (4/3)

28/21 in simplest form is 4/3.

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A flying cannonball’s height is described by formula y=−16t^2+300t. Find the highest point of its trajectory. In how many second
Yakvenalex [24]
<span>Highest point = 1406.25 Number of seconds = 9.375 We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375 So let's calculate the height at t = 9.375. y = -16t^2 + 300t y = -16(9.375)^2 + 300(9.375) y = -16(87.890625) + 300(9.375) y = -1406.25 + 2812.5 y = 1406.25 So the highest point will be 1406.25 after 9.375 seconds. Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.' y = -16t^2 + 300t y = -16(9.375 + e)^2 + 300(9.375 + e) y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e) y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e y = 1406.25 - 16e^2 Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
4 0
3 years ago
Three nine four dot 6 divided by nine
bogdanovich [222]
394.6÷9=43.84 your answer is this perhaps
7 0
3 years ago
Read 2 more answers
(5x^4-2x^3-7x^2-39)÷(x^2+2x-4)
lana [24]

Using the Polynomial Division: Divide 5x^{4}−2x^{3} -7x^{2} -39 by x^{2} +2x−4 using long polynomial division.

Answer to the Polynomial Division: 5x^{2} -12x+37+\frac{-122x+109}{x^{2}+2x-4}


4 0
3 years ago
(1 point) the equation for a parabola has the form y=ax2+bx+cy=ax2+bx+c, where aa, bb, and cc are constants and a≠0a≠0. find an
Kryger [21]
A graphing calculator working the quadratic regression problem for these three points gives the equation as

y = 2x² +7x -5

5 0
3 years ago
Solve the quadratic equation by completing the square.
Step2247 [10]

Answer:

x1, x2 = 4.74 , -2.74

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 2x - 13

a = 1     b = -2    c = -13

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1

x1 = (2 + √ (4 + 52)) / 2

x1 = (2 + √ 56 ) / 2

x1 = (2 + 7.48) / 2

x1 = 9.48 / 2

x1 = 4.74

x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1

x2 = (2 - √ (4 + 52)) / 2

x2 = (2 - √ 56 ) / 2

x2 = (2 - 7.48) / 2

x2 = -5.48 / 2

x2 = -2.74

6 0
3 years ago
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