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nadezda [96]
3 years ago
8

Does (6,3) make the inequality 16x+20y≤5 true?

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

156 ≤ 5 (Which is wrong)

Step-by-step explanation:

You start with:

16(6)+20(3) ≤ 5

96+60 ≤5

156 ≤5

Which is wrong.

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2. Consider the function, f(x)=x^3+x^2-9x-9
Sedaia [141]

The intercepts of the graph are:

x-axis interception: \left(-1,\:0\right),\:\left(-3,\:0\right),\:\left(3,\:0\right).

y-axis interception: \left(0,\:-9\right).

See the graph of the function f(x)=x^3+x^2-9x-9  in the attached image.

<h3>Constructing a graph</h3>

For constructing a graph we have the following steps:

  • Determine the range of values for x of your graph.

For this exercise, for example, we can define a range -4<x<4.  In others words, the values of x will be in this interval.

  • Determine the points

Replace these x-values in the given equation. For example:

When x=-4, we will have: \left(-4\right)^3+\left(-4\right)^2-9\left(-4\right)-9=-21.  Do this for the all x-values of your ranges.

See the results for this step in the attached table.

  • Draw the graph

Mark the points <u>x</u> and<u> y</u> that you found in the last step. After that, connect the dots to draw the graph.

The attached image shows the graph for the given function.

<h3>Find the x- and y-intercepts</h3>

The intercepts are points that crosses the axes of your plot. From your graph is possible to see:

x-axis interception points (y=f(x)=0)  are: \left(-1,\:0\right),\:\left(-3,\:0\right),\:\left(3,\:0\right).

y-axis interception point (x=0) is: \left(0,\:-9\right).

Learn more about intercepts of the graph here:

brainly.com/question/4504979

5 0
2 years ago
How do you solve a-9/a3
Klio2033 [76]
Is it this?
\frac{a - 9}{a3}
If so, then
\frac{a - 9}{a3}  = 0 \\  \frac{a}{a3}  -  \frac{9}{a3}  = 0 \\  \frac{1}{3}   -  \frac{9}{a3}  \\  \frac{1}{3}  =  \frac{9}{a3}  \\ 3( \frac{1}{3} ) = 3( \frac{9}{a3} ) \\ 1 =  \frac{9}{a}  \\ a = 9
5 0
3 years ago
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