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2 years ago

30 POINTS John opens a savings account and decides to deposit $10 each month. Let x represent the number of

Mathematics

1 answer:

tatuchka [14]2 years ago

7 0

Answer:

7.) y=10x

8.) $140 in 14 months, $60 in 6 months

9.) He will have saved $100 in 10 months and $175 in 17.5 months

10.) The rate of change is 10

11.) Knowing the rate of change helps you in answering this problem because it tells you how much money he saves per month.

12.)

0- $0

1- $10

2-$20

3-$30

4-$40

Step-by-step explanation:

7.) The standard form of a linear equation is y=mx+b

The starting balance is 0 so there is no point to adding b. M is the amount of money he deposits each month so that is 10. You plug in the values and you get y=10x (+0)

8.) y=10(14)

$140

y=10(6)

$60

9.) 100=10x

100/10= 10

10 months

175=10x

175/10=17.5

17.5 months

10.) The rate in change is m so 10.

Hope I explained this in simple enough terms. Have a good day!

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In 2008 the population of 10 to 14-year-olds in the United States was 24 84163 right this number in expanded form

Ket [755]

(2,000,000) + (400,000) + (80,000) + (4,000) + (100) + (60) + (3) = 2,484,163

6 0

3 years ago

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

3 0

2 years ago

Read 2 more answers

Find the distance between the

Dovator [93]

Answer:

$\displaystyle d = \sqrt{29}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Step-by-step explanation:

*Note:

The distance formula is derived from the Pythagorean Theorem.

Step 1: Define

Identify

Point (5, 10)

Point (10, 12)

Step 2: Find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(10 - 5)^2 + (12 -10)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{5^2 + 2^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{25 + 4}$
[√Radical] Add: $\displaystyle d = \sqrt{29}$

7 0

2 years ago

A truck is being filled with cube-shaped packages that have side lengths of 1/4 foot. The part of the truck that is being filled

n200080 [17]

Answer:

24000 pieces.

Step-by-step explanation:

Given:

Side lengths of cube = $\frac{1}{4} \ foot$

The part of the truck that is being filled is in the shape of a rectangular prism with dimensions of 8 ft x 6 1/4 ft x 7 1/2 ft.

Question asked:

What is the greatest number of packages that can fit in the truck?

Solution:

First of all we will find volume of cube, then volume of rectangular prism and then simply divide the volume of prism by volume of cube to find the greatest number of packages that can fit in the truck.

$Volume\ of\ cube =a^{3}$