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Ksju [112]
3 years ago
12

Vinny's friend told him that he could earn $49 for delivering newspapers. Vinny

Mathematics
1 answer:
Deffense [45]3 years ago
6 0

Answer:

The hourly rate would be 14

Step-by-step explanation:

All you have to do is divide 49 by 3.5, giving you 14 :)

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X square= 121 can anyone solve it
Alik [6]

Answer:

Picture is the answer.

Step-by-step explanation:

4 0
3 years ago
11. Little Sally Walker has a choice between going to an in-state college where she would pay
nalin [4]

Answer:

Step-by-step explanation:

Lets calculate first for in state college

yearly tuition fees = $3,500

monthly living expense = $700

one year has 12 months so yearly living expense =$700 * 12 = $8,400

Yearly expense of the in state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400)   = $3,500 + $8,400  = $11,900

____________________________________________________

Lets calculate first for  out of state college

yearly tuition fees = $6,000

monthly living expense = $400

one year has 12 months so yearly living expense =$400 * 12 = $4,800

Yearly expense of the out of state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400)   = $6,000 + $4,800  = $10,800

____________________________________________________

3 0
3 years ago
I need halp... QUESTION: tell weather the two figures are congruent. Explain your reasoning
Anastaziya [24]

number 3 is not congruent but number 4 is because #4 is basically the same thing but you cant really multiply something to question #3 to get those answers.

5 0
3 years ago
Read 2 more answers
15 pts + brainliest to right/best answer
asambeis [7]

Split the second term 7x^2 - 8x - 12 into two terms

7x^2 + 6x - 14x - 12

Factor out common terms in the first two terms, then in the last two terms

x(7x + 6) - 2(7x + 6)

Factor out the common term; 7x + 6

<u>(7x + 6)(x - 2) </u>

4 0
4 years ago
Read 2 more answers
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
3 years ago
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