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NeX [460]
2 years ago
6

Which is biggger -2/5 or -3/2

Mathematics
2 answers:
inn [45]2 years ago
5 0

Answer:

-2/5

Step-by-step explanation:

Gwar [14]2 years ago
3 0

Answer:

Step-by-step explanation:

-2/5

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What is 3/4 of a number minus -16 equals 28. what is the number
dalvyx [7]
3/4x - 16 = 28
         +16   +16
3/4x = 44
*3/4    *3/4
x = 176/3
7 0
3 years ago
If pqr = 1 , rst = 0 , and spr = 0, which of the following must be zero?
ahrayia [7]
P,Q,R can't be 0, because their product is nonzero. Either of S and T could be 0, but the third one only works if S is 0.
8 0
3 years ago
What is the value of the 5 in the number 7.522
joja [24]
Its 0.5. Which would be in fraction form 5/10 meaning its 5 tenths.
8 0
3 years ago
Please Help
Jlenok [28]

Histograms are useful when we have data which can be divided into several classes or groups. The histogram shows the trend of each class and the trend among the different classes. For example when we have about 50 different values ranging from 1 to 20, it will be a better approach to draw a histogram in this case by dividing the data into small ranges e.g 1 to 4, 5 to 9 and so on and counting the frequency for each class.

Dot plot is useful when we have a small number of individual values. In this case we can visualize how many times each individual value occurred in the data. This is useful when the number of values in the data is less.

In the given scenario, we have 12 values in total ranging from 1 to 5. So making a dot plot would be the best choice. A histogram would not be useful in this case.

Therefore, the correct answer is option D. Dot plot, because a small number of scores are reported individually

7 0
3 years ago
Read 2 more answers
The cosine law
romanna [79]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-------------------------------\\\\

\bf \cfrac{sin(88^o)}{39.9}=\cfrac{sin(A)}{31}\implies \cfrac{31\cdot  sin(88^o)}{39.9}=sin(A)
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot  sin(88^o)}{39.9} \right]=sin^{-1}\left[ sin(A) \right]
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot  sin(88^o)}{39.9} \right]=\measuredangle A
\\\\\\
50.93841^o\approx \measuredangle A\qquad thus\qquad \measuredangle C\approx 41.0619^o
3 0
3 years ago
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