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iren2701 [21]
3 years ago
15

Help looks like i forgot to read a ruler

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0

Answer:

D. 4 1/4

Step-by-step explanation:

hope it helps!! good luck:)

schepotkina [342]3 years ago
5 0

Answer:

4 1/4

Step-by-step explanation:

it looks like 4 and 1/4

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How many divisors of 63 are also divisors of 72? (Recall that divisors may be positive or negative.)
frutty [35]

1, 3, 9 and -1, -3, and -9 i guess

hope this helps

8 0
3 years ago
How do you solve #3? The one that is incorrect.
Sunny_sXe [5.5K]
Infinite they’re all multiples, so they are the same line
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2 years ago
Classify the following triangle check all that apply
IgorLugansk [536]
This triangle is obtuse( as it's one angle is greater than 90°) as well as isosceles (as it's two sides are equal).
7 0
4 years ago
Read 2 more answers
In the figure, ∆BAT ≅ ∆CAT. Which statement is not true by CPCTC? ∠CAB ≅ ∠SAB ∠CAS ≅ ∠BAS
Studentka2010 [4]

Answer:

∠CAB ≅ ∠SAB is not true

Step-by-step explanation:

CPCTC means id ABC = XYZ, than A=X, AB=XY, C=Z and so on. Basically the number numbers that come in the same order as the other one is equal.

So ∠CAS ≅ ∠BAS is true but ∠CAB ≅ ∠SAB is not.

Hope this helps. If you have any follow-up questions, feel free to ask.

Have a great day! :)

8 0
3 years ago
Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0
3 years ago
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