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iren2701 [21]
3 years ago
15

Help looks like i forgot to read a ruler

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0

Answer:

D. 4 1/4

Step-by-step explanation:

hope it helps!! good luck:)

schepotkina [342]3 years ago
5 0

Answer:

4 1/4

Step-by-step explanation:

it looks like 4 and 1/4

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What is the discriminant of the quadratic equation 0=2x^2 + 3x -5? 0-37 -31 0 43 049​
Vera_Pavlovna [14]

Answer:

Discriminant = b²-4ac

from 2x²+3x-5=0

a = 2 b = 3 and c = -5

Discriminant = 3² - 4(2)(-5)

= 9+40

= 49

Discriminant = 49

Ans = 49

6 0
2 years ago
The distribution of weights of United States pennies is approximately normal with a mean of 2.5 grams and a standard deviation o
stich3 [128]

Answer:

a) P(X

b) \bar X \sim N(2.5, \frac{0.03}{\sqrt{10}}=0.00948)

c) P(\bar X

And using a calculator, excel or the normal standard table we have that:

P(Z

d) Figure attached

e) If we don't know the distribution then we can't ensure that the sample mean would be distributed like this:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can't estimate the probabilities on a easy way.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(2.5,0.03)  

Where \mu=2.5 and \sigma=0.03

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability on this way:

P(-0.50

Part b

Since the distribution for X is normal then the distribution for the sample mean is:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(2.5, \frac{0.03}{\sqrt{10}}=0.00948)

Part c

P(\bar X

And using a calculator, excel or the normal standard table we have that:

P(Z

Part d

See the figure attached the deviation for the sample mean is lower for this reason we have the pattern in the graph attached.

Part e

If we don't know the distribution then we can't ensure that the sample mean would be distributed like this:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can't estimate the probabilities on a easy way.

4 0
3 years ago
A card is chosen at random from a deck of 52 cards it is replaced and a second card is chosen what is the probability both cards
marissa [1.9K]

the answer is 0.6% hope this helps


3 0
3 years ago
Read 2 more answers
the cell phone bill recorded that Jeremiah sent 532 text messages last week. On average how many text messages did he send each
Alik [6]

Answer:

76 messages

Step-by-step explanation:

532 divided by 7 = 76

5 0
3 years ago
Read 2 more answers
The measures of the angles of a triangle are shown in the figure below. Find the
dimaraw [331]

Answer:

318.6

Step-by-step explanation:

(3x-9) + (x+15) = 180

3x (x+15) -9 (x+15)

4x + 45x - 9x + 6 = 180

40x + 6 = 180

40x = 180 - 6

40x = 174

x = 4.34

(3x-9) = 4.34 * 3x-9 = 4.02

(x+15) = 4.34 + 15 = 19.34

180 - (4.02 + 19.34)

= 180 - 23.36

= 156.64

hope this answer helps!!

6 0
3 years ago
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