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balu736 [363]
3 years ago
7

The cat is 12 feet above the ground and the ladder is 9 feet away from the tree because of the mud. How long does the ladder nee

ds to be to reach the tree
Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

15 feet

Step-by-step explanation:

The ladder is the hypotenuse of a right triangle, with the legs being 9 ft and 12 ft long (see the picture).

To solve for the length of the ladder, use the Pythagorean Theorem.

9^{2} +12^{2} =c^{2} \\c=\sqrt{9^{2} +12^{2}} \\c=\sqrt{81+144} \\c=\sqrt{225} \\c=15

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980.18 cm^3

Step-by-step explanation:

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 now subtract the volume of the TWO spheres

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for result = 980.18 cm^3

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2 years ago
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8 0
3 years ago
Read 2 more answers
Can someone help me with this thanks ​
Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}

\frac{BC}{sinA}=\frac{AB}{sinC}

\frac{2}{sin25}=\frac{3}{sinC}

\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

\frac{BC}{sinA}=\frac{AC}{SinB}

\frac{2}{sin25}=\frac{l}{sin(115.66)}

l=\frac{2\times sin(115.66)}{sin25}

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

brainly.com/question/25852087

#SPJ1

8 0
2 years ago
Two points located on are J(1,-4) and K(-2,8). What is the slope of ?
trapecia [35]

Answer:

-4

Step-by-step explanation:

to do this you use y2-y1/x2-x1

so this would be -4-8/1- - 2

-12/3 = -4

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2 years ago
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