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LuckyWell [14K]
3 years ago
7

Help pls I really need this

Mathematics
1 answer:
creativ13 [48]3 years ago
5 0

Answer:

it's A

Step-by-step explanation:

sorry if its wrong

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You deposit $75 in a savings account that earns 5% annual interest compounded yearly. Find the balance in the account after the
Nana76 [90]
Hi there
The formula is
A=p (1+r)^t
A future value
P present value 75
R interest rate 0.05
T time

After 1 year the balance is
A=75×(1+0.05)
A=78.75

After 2 years
A=75×(1+0.05)^(2)
A=82.69

After 5 years
A=75×(1+0.05)^(5)
A=95.72

After 20 years
A=75×(1+0.05)^(20)
A=198.99 round
A=199

Hope it helps
7 0
3 years ago
Legend has it that a bull sasquatch in rut will howl approximately 9 times per hour when it is 40°f outside and only 5 times per
ahrayia [7]

The answer is 13.

To solve this question, you need to determine the slope of the function. if howl  is y and the temperature is x of the graph, the slope would be:

9-5/(40-70)= 4/-30= -2/15

Using one of the point and the slope, you can find the number of howl

-2/15= 9-y/40-(-20)

9-y= -2/15 * 60

9-y= -4

y= 9+4= 13

8 0
4 years ago
You move up 4 units and right 2 units. You end at (-1, 3). Where did you start?
Delicious77 [7]

Answer:

at the begining

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Jkl is an equilateral triangle jk= 13x+5,KL= 17X-19 AND JL= 8X+35​
stira [4]

Answer:

x = 6

Step-by-step explanation:

Since the triangle is equilateral then sides are congruent.

Equate any 2 sides and solve for x

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

JK = (13 × 6) + 5 = 78 + 5 = 83

KL = (17 × 6) - 19 = 102 - 19 = 83

JL = (8 × 6) + 35 = 48 + 35 = 83

ΔJKL is equilateral with side = 83

4 0
3 years ago
There are 20 parrots at the animal sanctuary. Their population is increasing at a rate of 15% per year. There are also 24 snakes
worty [1.4K]
For the answer to the questions above,
A) Parrots are following a Geometric Progression of 15% increase.

20(1.15),  20(1.15)², 20(1.15)³,

Function  = 20(1.15)^n      Where n is at the end of year, n =1, 2, 3, ..

Snakes are increasing by 4.

28, 32, 36,....

Function =  24 + 4n          n = number of end year,      n =1, 2, 3,...

<span>B) After 10 years:              </span>
Parrot =  20(1.15)¹⁰    = 80.91115471

Snakes =  24 + 4(10) = 64

<span>C) After what time they are the same: </span>
We use trial and error:


Test:  n                             20(1.15^n)                        (24 + 4n)
          1                                    23                                   28
          2                                    26.45                              32
<span>          3                                    30.41                             36    </span>
          4                                    34.98                              40
          5                                    40.23                              44
          6                                    46.26                              48
          7                                    53.20                              52
          8                                    61.18                              56
          9                                    70.36                              60

After year 7, the Parrots increases far more.
<span>At year 7 they are roughly the same.</span>
8 0
4 years ago
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