Answer:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
Step-by-step explanation:
Solve for b:
b - (3 + 2/5) = 8 + 1/5
Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:
b - (5×3)/5 + 2/5 = 8 + 1/5
5×3 = 15:
b - (15/5 + 2/5) = 8 + 1/5
15/5 + 2/5 = (15 + 2)/5:
b - (15 + 2)/5 = 8 + 1/5
15 + 2 = 17:
b - 17/5 = 8 + 1/5
Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:
(5 b)/5 - 17/5 = 8 + 1/5
(5 b)/5 - 17/5 = (5 b - 17)/5:
(5 b - 17)/5 = 8 + 1/5
Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:
(5 b - 17)/5 = (5×8)/5 + 1/5
5×8 = 40:
(5 b - 17)/5 = 40/5 + 1/5
40/5 + 1/5 = (40 + 1)/5:
(5 b - 17)/5 = (40 + 1)/5
40 + 1 = 41:
(5 b - 17)/5 = 41/5
Multiply both sides of (5 b - 17)/5 = 41/5 by 5:
(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 41
Add 17 to both sides:
5 b + (17 - 17) = 17 + 41
17 - 17 = 0:
5 b = 41 + 17
41 + 17 = 58:
5 b = 58
Divide both sides of 5 b = 58 by 5:
(5 b)/5 = 58/5
5/5 = 1:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
Answer:
A
Step-by-step explanation:
youre looking for the total spent, and then each variable from the word equation
Answer:
Relative frequency is 7.41% or 0.0741
Step-by-step explanation:
Given
The Attached Table
Required
Calculate the relative frequency of the class with lower limit 27
Relative Frequency is calculated by dividing individual frequency by the total frequency
Mathematically,
The total frequency of the given data is 6+8+4+2+5+2
The class with lower limit 27 has a frequency of 2;
Hence;
becomes
(Approximated)
You may also leave your answer in percentage form
Hence, the relative frequency is 7.41% or 0.0741
Answer:
Answer b)
Step-by-step explanation:
In the sequence 0, 5, 10, 15,...
5 is added to each term in order to get the next one. Therefore the next three terms would be; 20, 25, 30.
This agrees with answer b) in the list of possible answers.
