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levacccp [35]
3 years ago
11

Please help me on 5 I don’t get it LOL 11 point pleaseeee

Mathematics
1 answer:
kramer3 years ago
8 0

Answer:

Hello there! the answer would be H, 1/36

Step-by-step explanation:

I hope you have a great day!

You might be interested in
For a circle radius of 8 feet, find the arc length s if the central angle is 10*
ser-zykov [4K]

Answer:

The correct answer is Option 1: s = 4/9pi feet

Step-by-step explanation:

Given that

The radius of circle is 8 feet

r = 8

Central angle is:10°

The arc length is denoted by s and is calculated by the formula:

s = 2\pi r.\frac{x}{360 \textdegree}

Here x is the central angle

Putting the known values we will get:

s = 2\pi (8).\frac{10 \textdegree}{360 \textdegree}\\s = 16\pi . (\frac{1}{36})\\s = \frac{16\pi}{36}\\s = \frac{4}{9} \pi

The arc length is 4/9 pi feet.

Hence,

The correct answer is Option 1: s = 4/9pi feet

8 0
3 years ago
This is the last question somebody help.
arlik [135]
5(7)-5
———-
3(7)-16

= 54
3 0
3 years ago
Read 2 more answers
Solve the equation; 3a/4-2a/3=7/4
DiKsa [7]

Answer:  " a = 21 " .

 _____________________

<u>Step-by-step explanation</u>:

Given:  3a/4-2a/3 = 7/4 ;  Solve for "a" ;

Rewrite as: (3a/4) - (2a/3) = (7/4) ;

Now, for each of the three (3) "denominator values" in "fraction form" within the equation given:

      → Find the "LCD" ["Least Common Denominator"]:
The denominators are:  4, 3, and 4 ;  

 that is:  "3" and "4" ;
 ____

To find the LCD: First; multiply the denominators:  "4 * 3 = 12" .
 So; the value "12" could be the LCD;  so, the value for the LCD is no greater than "12" ; however, there <u><em>could </em></u>be a smaller value.
To determine the LCD:
List the multiples of the given denominators:
____
3: 3, 6, 9, <u><em>12</em></u>, 15 .... ;
4: 4, 8, <u><em>12</em></u>, 16... ;
____
We find that "12" is, in fact, the LCD of "3" and 4:
____
We can multiply each side of the equation by "12" ; to eliminate the "fractional values" :
____
   12*[\frac{3a}{4} - \frac{2a}{3}] = 12*[{\frac{7}{4}]
____
<u>Note the</u><u> "</u><u>distributive property</u><u>"</u><u> of multiplication</u>:
  →  a(b+c) = ab + ac ;

____

As such:
12*[\frac{3a}{4} - \frac{2a}{3}] = 12*[{\frac{7}{4}] ;

____
Let us start with the "left-hand side" of the equation:
____
12*[\frac{3a}{4} - \frac{2a}{3}] ;

 =  [12*\frac{3a}{4}] + [-12 * \frac{2a}{3}] ;
 =  [12*\frac{3a}{4}] - [12 * \frac{2a}{3}] ;
____
Note:  "  [12*\frac{3a}{4}] " ;

                     = \frac{12}{1} * \frac{3a}{4} ;

       →  The "12" cancels to a "3" ; and the "4" cancels to a "1" ;
 since: "12÷4 = 3" ; and since:  "4÷4 = 1" ;
       → and we can rewrite the "left-hand-side" expression as:
       →  "   \frac{3}{1} * \frac{3a}{1} " ;  which we can simplify as:  

               →  "3 * 3a" ; which we can simplify as:  " 9a " .
then we have:  " [12 * \frac{2a}{3} ] " ;

 which equals:
 =   " \frac{12}{1} * \frac{2a}{3} " ;
<u>Note</u>: The "12" cancels out to a "4"; & the "3" cancels out to a "1" ;

  →  {since:  "(12 ÷ 3 = 4)"; & since: "(3 ÷ 3 = 1)" ;
____
→ And we can rewrite the expression as:
     →  " \frac{4}{1} *\frac{2a}{1} " ;  which we can simplify as:
     →  " 4 * 2a " ; which we can simplify/calculation as:  " 8a " ;
Now, we can rewrite the expression of the "left-hand side"
of the equation as:
____
    →  " [9a] − [8a] " ; (don't forget to carry down the "minus sign"!) ;
which we can simplify/calculate to get:
  →  " [9a − 8a] " ;  which we can further simplify/calculate;

  →  to get:
        → " 1a " ;  or:  "a" —the value for which we wish to solve!
 ____
Now, let us examine the "right-hand side" of the equation:
 ____

→  " \frac{12}{1}  * \frac{7}{4} " ;
<u>Note</u>:  The "12" cancels out to a "3" ; & the "4" cancels out to a "1" ;
       → {Since:  "12 ÷4 = 3 " ;  &  since:  "4 ÷ 4 = 1 "} ;

And we can rewrite the expression as:  
    →  " \frac{3}{1} * \frac{7}{1} " ; which we can simplify as:
           → " 3 * 7 " ;  which can simplify/calculate to get:  " 21" ;
⇒  Now, let us rewrite the equation; by using our simplified values for both the "left-hand side" and the "right-hand side" of the equation; to solve for "a" :
 ⇒  a = 21 ;  

→  which is the correct answer:  
        → " a = 21 " .
 ____
  Hope this helps!

 ____

6 0
2 years ago
What is one tenth of .5
malfutka [58]
0.05 would be 1/10 of 0.5
8 0
4 years ago
help with this you guys i know im asking to many questions and sorry because im going to keep asking them.
Aleonysh [2.5K]

D is your answer please like this answer

5 0
3 years ago
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