Et's give this a go:h(x) = cos(x) / f(x)
derivative (recall the quotient rule)h'(x) = [ f(x) * (-sin(x)) - cos(x)*f'(x) ] / [ f(x) ]^2
simplifyh'(x) = [ -sin(x)*f(x) - cox(x)*f '(x) ] / [ f(x) ]^2h'(π/3) = [ -sin(π/3)*f(π/3) - cox(π/3)*f '(π/3) ] / [ f(π/3) ]^2h'(π/3) = −(3–√/2)∗(3)−(1/2)∗(−7)/(3)2
h'(π/3) = (−33–√/2+7/2)/9
And you can further simplify if you want, I'll stop there.
The negative 4 in the parenthesis caused the graph to move four units to the right.
Answer:
See explanations below
Step-by-step explanation:
Given the functions f(x)=2x+3 and g(x)=x^2-1
a. Find f(g(x))
f(g(x)) = f(x^2-1)
f(g(x)) = 2(x^2-1)+3
f(g(x))= 2x^2-2+3
f(g(x)) = 2x^2+1
Hence the composite function f(g(x)) is 2x^2+1
b) g(f(x)) = g(2x+3)
g(f(x) = (2x+3)^2-1
g(f(x)) = 4x^2+12x+9-1
g(f(x)) = 4x^2+12x+8
Answer:
miles per minute represents the speed of the bird and 3 miles represents the original distance of the bird from its nest.
Step-by-step explanation:
As there is no graph mentioned here but the information are quite sufficient to answer the question.
We have points 
From these points we can find the slope of the line .
From point slope formula 
And assigning 
and 
This slope is also the speed of the bird which is 
As by plugging the values of any coordinate point we can confirm this.
Lets put 
, y-axis is the distance so in 
minutes the the distance covered by the bird must be equal to to y-axis value which is 
miles.
Now as in 
the bird has started from y-intercept value 
so we can say that,the original distance of the bird from its nest is 
.
So the correct choices are:
and 
The birds speed is 
per minute and is away from its nest.
Answer:
I think it may be 120 cm
Step-by-step explanation:
A F is 13 using pythagorean theorem on triangle CED and applying the hypotenuse length to A F.
ABC is similar to triangle CED and is dilated by a factor of 3 so the base is 36.
using pythagorean theorem on triangle ABC gets the hypotenuse length of 39 which can be applied to FE
add all the values together
39 + 13 + 15 + 36 +12 +5 = 120
