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3 years ago

Use the figure below to complete Parts A and B.

Mathematics

1 answer:

aleksklad [387]3 years ago

5 0

Help me! I’ll mark you brainly!ikzkkkdidjkknujjdididiidiwisisiisudusisisusuususususjsusjsjsjjsuusususususuususususuusususuusususidkdkkdiidididisklslsdksiisusskksjajjjjsjsjjjjjjjjjkkkkjjskkssiisiusiwiisis

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8 less than one third of x is y.

Andre45 [30]

1/3x - 8 = y <== ur equation

4 0

3 years ago

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Which pair is made up of prime numbers 11 & 33 , 42 & 56 , 37 & 67, 57 & 97

Cerrena [4.2K]

Answer:

37 & 67

Step-by-step explanation:

11 & 33

11 - 1, 11

11 is prime

33 - 1, 3, 11, 33

33 is composite number

11 & 33 is incorrect

42 & 56

42 - 1, 2, 3, 6, 7, 14, 21, 42
56 - 1, 2, 4, 7, 8, 14, 28, 56
Both 42 and 56 are composite numbers
42 & 56 is incorrect

37 & 67

37 - 1, 37
67 - 1, 67
Both 37 and 67 are prime numbers
37 & 56 is correct

57 & 97

57 - 1, 3, 19, 57
97 - 1, 97
57 is a composite number, 97 is a prime number
57 & 97 is incorrect

3 0

3 years ago

Which point is located at (2, -3)?point Hpoint Epoint Gpoint K

Fynjy0 [20]

Answer:

Since i dont have a graph il just tell you this way. on the x axis, go right 2 times, then go down 3 times and that will be your answer.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Manuel earns $7.25 per hour helping his neighbor. Last month he earned $348. Choose the correct equation and solution which dete

zysi [14]

Answer:

Number of hours= 48 hours

Step-by-step explanation:

Giving the following information:

Hourly rate= $7.25

Total earned= $348

<u>To calculate the number of hours worked, we need to use the following formula:</u>

Total earned= hourly rate*number of hours

number of hours= total earned / hourly rate

number of hours= 348 / 7.25

number of hours= 48 hours

6 0

3 years ago

Estimates of the number of cells in the human body vary over an order of magnitude. Indeed, the precise number varies from one

Amiraneli [1.4K]

Answer:

a) 2.00 × 10¹⁰; b) 2.00 × 10¹³

Step-by-step explanation:

a) No. of cells in 1 cm³

$\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}$

b) No. of cells in 1 L

$\text{No. of cells} = \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}$

7 0

3 years ago