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Keith_Richards [23]
3 years ago
13

Use the figure below to complete Parts A and B.

Mathematics
1 answer:
aleksklad [387]3 years ago
5 0
Help me! I’ll mark you brainly!ikzkkkdidjkknujjdididiidiwisisiisudusisisusuususususjsusjsjsjjsuusususususuususususuusususuusususidkdkkdiidididisklslsdksiisusskksjajjjjsjsjjjjjjjjjkkkkjjskkssiisiusiwiisis
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Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
3 years ago
Which congruence theorem can be used to prove △WXS ≅ △YZS? Triangles W X S and Y Z S are connected at point S. Angles W X S and
iVinArrow [24]

Point S makes the two connected angles the same. They both have right angles.

And one side of each is congruent.

This means you know 2 angles are the same and one side is the same.

You would use ASA (Angle, Side, Angle)

3 0
3 years ago
Read 2 more answers
Given: -2x &lt; 10. Choose the solution set.
nadya68 [22]

Answer:

C

Step-by-step explanation:

given - 2x < 10 ( divide both sides by - 2 )

Remembering that the symbol is reversed when multiplying/ dividing by a negative quantity.

x > - 5 ← note reversal of symbol

solution is {x | x > - 5 } → C


4 0
3 years ago
2/3 and 5/6 common denominator
m_a_m_a [10]
The common denominator would be 6. Since, the least common multiple of 3 and 6 is 6.
3:
3, 6, 9
6:
6, 12, 18
Least common multiple is 6
7 0
3 years ago
How to find maximum and minimum values of a parabola
Arturiano [62]

Answer:

Step-by-step explanation:

Finding max/min: There are two ways to find the absolute maximum/minimum value for f(x) = ax2 + bx + c: Put the quadratic in standard form f(x) = a(x − h)2 + k, and the absolute maximum/minimum value is k and it occurs at x = h. If a > 0, then the parabola opens up, and it is a minimum functional value of f.

4 0
2 years ago
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