Answer:
$17,000 Favorable
Explanation:
Provided information, we have
Standard hours for each unit = 0.8 hours
Standard Rate per hour = $34
Actual quantity produced = 7,650 units
Actual labor hours used = 5,620
Actual rate per hour = $118,020/5,620 = $21 per hour
Standard hours for Actual output = 7,650 
0.8 = 6,120 hours
Labor Efficiency Variance = (Standard Hours - Actual Hours) Standard labor rate per hour
= (6,120 - 5,620) $34
= $17,000 Favorable
As the amount is positive and actual hours used is less than standard hours the variance is favorable.
The waiting time at which 10 percent of the people would continue to hold is given as 2.3
<h3>How to solve for the waiting time</h3>
We have to solve for X ~ Exponential(λ).
then E(X) = 1/λ = 3,
= 0.3333
Remember that the cumulative distribution function of X is F(x) = 1 - e^(-λx). ; x is equal to the time in over case
For 10 percent of the people we would have a probability of
10/100 = 0.1
we are to find
P(X ≤ t)
= 1 - e^(0.3333)(t) = 0.1
Our concern is the value of t
Then we take the like terms
1-0.1 = e^(0.3333)(t)
1/0.9 = e^(0.3333)(t)
t = 3 * ln(1/0.9)
= 0.3157
Answer:
a. $2,200,000
Explanation:
We solve considering the inventory identity:
the difference during the year means the difference between ending and beginning inventory was of 200,000
So we plug that into the formula and solve
Purchase 2,200,000
JOBS ARE THE SOURCE OF INCOME
