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icang [17]
2 years ago
7

3 Jazmin is mailing two packages. One package weighs 3 pounds, and the other package weighs 20 ounces. What is the total weight

of both packages? (1 pound = 16 ounces)​
Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
8 0

Answer:

68oz

Step-by-step explanation:

1) 3lbs x 16oz = 48

Now we know 3lbs is 48oz. since one pound is 16 ounces, 3 pounds is 48 ounces.

2) 48 + 20 = 68oz

3) The total weight of both packages is 68 ounces.

Jesus loves ya, have a great day!

---------------------

John 8:12 - When Jesus spoke again to the people, he said, "I am the light of the world. Whoever follows me will never walk in darkness, but will have the light of life."

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How does 17- (-15) compare to 17-0
pentagon [3]
17-(-15)=32
17-0=0
They are not equivalent so they are different.
Also for future reference when you have 2 minus signs they equal a addition sign.
Hope this helps :) GL
4 0
2 years ago
Find the average rate of change of each function over the interval [0, 2]. Match each representation with its respective average
marishachu [46]
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2

1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4

2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5

3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2

4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6

Answer:
Pairs
1) h(x)     4
2) f(x)      5
3) g(x)     2
4) j(x)     -6
8 0
3 years ago
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damaskus [11]
Wowowowoow okokokokokok
5 0
2 years ago
Read 2 more answers
Hellllpppp plsssss just click the picture then you see it
Solnce55 [7]

Answer:

1. 8 + 13 = 13 + 8.

2. 6 + ( 12 + 4) = 6 + ( 4 + 12).

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank
strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water (Q), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

Q = \dot Q \cdot \Delta t (1)

Where:

\dot Q - Volume rate, measured in feet per minute.

\Delta t - Time, measured in minutes.

If we know that \dot Q = 2000\,\frac{gal}{min} and \Delta t = 120\,min, then the amount of water is:

Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)

Q = 32160\,ft^{3}

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

Q = \frac{\pi}{4}\cdot D^{2}\cdot h (2)

Where:

D - Diameter, measured in feet.

h - Height, measured in feet.

If we know that Q = 32160\,ft^{3} and h = 12\,ft, then the minimum diameter is:

D^{2} = \frac{4\cdot Q}{\pi\cdot h}

D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }

D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }

D \approx 58.415\,ft

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0
2 years ago
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