The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
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Answer:
About Points
S = (x,y) searched point (it will be in the third quadrant )
M = (-2,0) Midpoint | SP |
P = (3,5) one end of the segment | SP |
You have to draw Cartesian.
we set in a point M and P. We both points by a simple and we extend it for the third quarter of the system. Compass measure the distance from the point M to the point P. From the point M we set a compass point S. Figure attached. Received point S = ( -7 , -5 ) . It sought a point that calculate .
We use the information that | SM | = | MP |
Answer : S = (-7,-5)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Area of a square = s²
s is the side length of the square
Given
s = 2^{7 1/2}
s = 2^15/2
Area = ( 2^15/2)²
Area = 2^15
Hence two area of the square is 2^15 inches
Answer:
1/3
Step-by-step explanation:
pic bleow
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56 dived by 2 equals 28. 28=green ribbon. Brown ribbon is 4 times as long. 28 times 4 equals 112. The brown ribbon is 112 cm long.
