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PolarNik [594]
2 years ago
7

Please answer the question attached in the pic

Mathematics
1 answer:
pantera1 [17]2 years ago
5 0

Answer:

(25)^2*(9)^2*(4squreroot2)^2*(7squreroot2)^2

Step-by-step explanation:

5^4*3^3*2^5*343

=(25)^2*(9)^2*(4squreroot2)^2*(7squreroot2)^2

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Triangle XYZ is translated 4 units up and 3 units left to yield ΔXYZ. What is the distance between any two corresponding points
Mashcka [7]
<h3>Answer:</h3>

5 units

<h3>Step-by-step explanation:</h3>

A point 4 up and 3 over from its original location has moved a distance that can be found using the Pythagorean theorem.

... d² = 4² +3² = 16 +9 = 25

... d = √25 = 5 . . . . units

7 0
3 years ago
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Help Me Help Me Help!!!!
lions [1.4K]
X=6 because
9-6=3

X=3 because
2•3=6

X=2 because
1.5 or 1 1/2 • 2 = 3

Not sure if this was what you needed or not!
3 0
3 years ago
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Which of the following equations is used to find the value of c?
erica [24]

Answer:

D. a^{2} + b^{2} = c^{2}

Step-by-step explanation:

Pythagorean Theorem

5 0
2 years ago
Read 2 more answers
Consider the equations 15x + 9y = 45 and 9x + 8y = 12. Solve the system of equations using elimination. Give your solution to th
True [87]

Answer:

(-5.77, 6.46)

Step-by-step explanation:

15x + 9y = 45 ----------- i

9x + 8y = 12----------------ii

Multiply equation i by 9 the coefficient of x in equ ii

And equation ii by 15 the coefficient of x in equ I

9 x 15x + 9y = 45 ----------- i

15 x 9x + 8y = 12----------------ii

135x+81y = 405

135x+120y= 180

Subtract equation ii from I

135x-135x+81y-(+120y)= 405-180

-39y=225

y = 225/-39 = -5.77

Insert the value of y in equ i

15x + 9y = 45

15x+9(-5.77) = 45

15x-51.92=45

15x = 45+51.92

15x= 96.92

x = 96.92/15= 6.46

(x,y) = (-5.77, 6.46)

x = 6.92/15

5 0
3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
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