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3 years ago

What is the simplified form of -64 1/3? Need Help ASAP, will make brainliest answer :)!!!

1 answer:

7 0

-64 1/3

disregard the negative sign for the moment...
to turn a mixed number into an improper fraction, take ur whole number (63) and multiply it by ur denominator (3) and u get (64 * 3) = 192....now add that to ur numerator (1) and u get (192 + 1) = 193...now put that over ur original denominator (3) and u get 193/3.....now put ur negative sign back....and u have - 193/3.....simplified form, does not reduce

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I need an answer QUICK

denpristay [2]

I believe it would be 264

3 0

3 years ago

Factor the gcf out of the expression: -6x^3 - 9xy + 18x

Westkost [7]

Answer:

-207xy

Step-by-step explanation:

-6x^3 - 9xy + 18x

-216x -9xy +18x

-225xy + 18x

-207xy

If I'm not mistaken.

6 0

3 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

Pre-calc<br> Evaluate f(2) using substitution:<br> f(x) = 2x^3 – 3x^2– 18x-8

krek1111 [17]

Answer:

f(2) = -40

Step-by-step explanation:

Just substitute x=2 into the function:

f(x) = 2x³ - 3x² - 18x - 8

f(2) = 2(2)³ - 3(2)² - 18(2) - 8

f(2) = 2(8) - 3(4) - 36 - 8

f(2) = 16 - 12 - 44

f(2) = 4 - 44

f(2) = -40

8 0

2 years ago

Write the fraction in simplest form of 6/20.

nikklg [1K]

$\dfrac{6}{20}=\dfrac{6:2}{20:2}=\dfrac{3}{10}$

8 0

3 years ago