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3 years ago

What is the domain of the square root function graphed below?

Mathematics

2 answers:

vaieri [72.5K]3 years ago

6 0

Answer:

x ≥ 3

Step-by-step explanation:

The domain is the set of x values in a function

The ordered pair ( 3 , 1 ) represents the point where the function starts

( note that the point is "closed" which means that ( 3 , 1 ) represents a solution to the function ) ( which also means that we will be using ≤ or ≥ )

The x value of that ordered pair is 3 which means that the domain must include 3.

The line then goes to the right of the x value 3, infinitely which means that the domain is anything greater than or equal to 3

or x ≥ 3

HACTEHA [7]3 years ago

4 0

Answer:

thanks for the points bye

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Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

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What is the domain of the square root function graphed below?​

What is the domain of the square root function graphed below?