if the tins are shown like this:
TIN A: 2:3
TIN B: 4:5
TIN A: can also be shown as 4:6
there for theirs is more blue in the first tin then second tin
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Answer:
4 pages
Step-by-step explanation:
48 divided by 12 = 4
Answer:
ok I will try solve your problem. good luck
Step-by-step explanation:
a. known: Bank balances : 3021 pesos
monthly withdrawals: 78 pesos
months of withdrawal: 12 months
b. asked: new bank balance?
c. equation: New bank balance= bank balance - ( monthly withdrawals X months of withdrawal)
d. New bank balance: 3021- (78x12)
= 3021 - 936
= 2085 pesos
e. my new bank balance is 2085 pesos.
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