5.5hours to drive264 miles
7 hours to drove (264÷5.5)× 7 =....
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
Answer:
n=3
Step-by-step explanation:
64^(1/3)
Note that the exponent 1/3 given stands for the third root of the integer.
64^(1/3) =4
Check: 4 x 4 x 4 = 64
(By comparison of 64^(1/3) to 64^(1/n) means n= 3)
∜(64^(1/3)) =∜(4) = 1.41421356
The real number is
All the roots are:
1.41421356
1.41421356i
−1.41421356
−1.41421356i
4 is not a perfect 4th power.
I'm not sure what you mean by rename
Answer:
-21x + 3y + 10
Step-by-step explanation:
10 - 4x + 3y - 17x
= -4x - 17x + 3y + 10
= -21x + 3y + 10
