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Pepsi [2]
3 years ago
5

When do these 2 lines intersect y = 3x-3, y = 2.3x+4

Mathematics
2 answers:
Volgvan3 years ago
6 0

Set the equations to equal each other:

3x-3 = 2.3x+ 4

Solve:

Subtract 2.3x from both sides

0.7x -3 = 4

Add 3 to both sides:

0.7x = 7

Divide both sides by 0.7

X =10

Solve for y:

Y = 3(10) -3

Y = 30-3

Y=27

The lines cross at (10,27)

Ganezh [65]3 years ago
5 0

Answer:

(10,27)

Step-by-step explanation:

Plot the <em>first point</em> of the <u>first line</u> by plotting the y-intercept of -3, and using the slope of 3 to plot the rest of the points needed (up 3, over 1).

Plot the <em>first point</em> of the <u>second line</u> by plotting the y-intercept of 4, and using the slope of 2.3 (23/10) to plot the rest of the points needed (up 23, over 10).

After a while of graphing, you will then find that the point of location in which these two lines intersect is (10,27).

Hope this helps :) Thanks!

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Answer:

0.128

Step-by-step explanation:

We know the probability for any event X is given by,

P(X=x)=\binom{n}{x}\times p^{n-x}\times q^{x},

where p is the probability of success and q is the probability of failure.

Here, we are given that p = 0.533.

Since, we have that q = 1 - p

i.e. q = 1 - 0.533

i.e. q = 0.467

It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.

Substituting the values in the above formula, we get,

P(X=4)=\binom{5}{4}\times 0.533^{5-4}\times 0.467^{4}

i.e. P(X=4)=5 \times 0.533 \times 0.048

i.e. P(X=4)=5 \times 0.533 \times 0.048

i.e. i.e. P(X=4)=0.128

Hence, the probability of 4 wins in the next 5 games is 0.128.

8 0
3 years ago
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Step-by-step explanation:

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