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3 years ago

You own a portfolio of two stocks, a and

1 answer:

7 0

Stock a is $2000. Calculate 10.5% of $2000, which equals $210.
Stock b is $3000. Calculate 14.7% of $3000, which is $441.

The expected return on the portfolio is $210 + $441, which equals $651.

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Classify each of the following based on the macroeconomic definitions of saving and investment:1. Saving Investment Kyoko borrow

r-ruslan [8.4K]

Answer

The classification is shown below:

Explanation:

The saving refers to the amount i.e above its consumption expenditure let us take an example if an individual salary is $100,000 and its expenditure assumes $50,000 then it saves $50,000 so the $50,000 is the savings. While the investment is the amount that is spent to buy some assets in terms of building, machinery, home, etc.

So the classification is presented below:

a. Kyoko borrows money to build a new lab for her engineering firm. = Investment

b. Rina purchases stock in Nano Speck, a biotech firm. = saving

c. Musashi takes out a mortgage for a new home in Detroit. = investment

d.Jacques purchases a corporate bond issued by a car company. = saving

6 0

2 years ago

You plan to invest in bonds that pay 6.0%, compounded annually. If you invest $10,000 today, how many years will it take for you

kati45 [8]

Answer:

The answer is 16 years.

Explanation:

The formula for calculating the value of an investment that is compounded annually is given by:

$V(n)=(1+R)^nP$

Where:

$n$ is the number of years the investment is compounded,

$R$ is the annual interest rate,

$P$ is the principal investment.

We know the following:

$25000=(1+0.06)^n \times 10000$

And we want to clear the value n from the equation.

The problem can be resolved as follows.

First step: divide each member of the equation by $10,000$ :

$\frac{ 25000}{10000}=(1+0.06)^n \times \frac{ 10000}{10000}$

$2.5=(1.06)^n$

Second step: apply logarithms to both members of the equation:

$log(2.5)=log (1.06)^n$

Third step: apply the logarithmic property $logA^n=n.logA$ in the second member of the equation:

$log(2.5)=n.log (1.06)$

Fourth step: divide both members of the equation by $log1.06$

$\frac{log(2.50)}{log (1.06)} =n$

$n= 15.7252$

We can round up the number and conclude that it will take 16 years for $10,000 invested today in bonds that pay 6% interest compounded annually, to grow to $25,000.

6 0

3 years ago

The primary purpose of __________ is to preserve memories of persons or events.

kupik [55]

monuments is the right answer

3 0

3 years ago

Luis has $170,000 in his retirement account at his present company. Because he is assuming a position with another company, Luis

serious [3.7K]

Answer:

Luis will have $ 1,153,675.657524 in his account at the time of his retirement.

Explanation:

Acording to the data Luis has $170,000 in his retirement account

His current account after 30 years at 4.5% compounded quarterly will be

Current account = $ 170,000(1 + (0.045/4))^(4*30)

Current account = $ 650,838.260724

Acording to the data Luis also plans to put $2000/quarter into the new account until his retirement 30 years from now.

The future value (FV) of the account will be

FV = 2000[(1 + (0.045/4))^(4*30) -1] / (0.045/4) 0.01125

FV = $ 502,837.3968

Therefore, to calculate how much will Luis have in his account at the time of his retirement we have to calculate the following:

Total amount = Current account+FV

Total amount = $ 650,838.260724 + $ 502,837.3968

Total amount = $ 1,153,675.657524

Luis will have $ 1,153,675.657524 in his account at the time of his retirement.

4 0

3 years ago

Cheryl was balancing the Trial Balance of the company. She found that the debit balance totaled $73,000 and the credit balance w

klio [65]

I think it is both sides

4 0

3 years ago

Read 2 more answers