Question

Plz help i need this answer to pass

Answer 1

Answer:

The equation in slope-intercept form of required line is: $\mathbf{y=\frac{2}{3}(x)-6}$

Step-by-step explanation:

We need to write equation in slope-intercept form to represent the line on the  graph.

The general equation in slope-intercept form is: $y=mx+b$

Where m is slope and b is y-intercept

Finding slope using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

Looking at he graph we have

$x_1=3, y_1=-4, x_2=6, y_2=-2$

Putting values in formula and finding slope:

$Slope=\frac{-2-(-4)}{6-3}\\\\Slope=\frac{-2+4}{3}\\Slope=\frac{2}{3}$

So, we get slope m = 2/3

Using slope m=2/3 and point (3,-4) we can find y-intercept

$y=mx+b\\\\-4=\frac{2}{3}( 3)+b\\-4=2+b\\b=-4-2\\b=-6$

So, y-intercept b = -6

The equation of line having m=2/3 and b=-6 will be:

$y=mx+b\\y=\frac{2}{3}(x)-6$

The equation in slope-intercept form of required line is: $\mathbf{y=\frac{2}{3}(x)-6}$