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2 years ago

A group of students must collect at least $150 to organize a science fair. They have

Mathematics

2 answers:

MariettaO [177]2 years ago

7 0

Can you attach a pic of the graphs so I can help?

Law Incorporation [45]2 years ago

6 0

The answer would be the first graph! The one that has the black dot in the number 120.

Hope this helps! :)

Have a nice day <3

~Amy

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What is the scale factor from polygon A to polygon B?

Arada [10]

You must divide the larger by the smaller... That will give you the scale factor.

For example: Rectangles 10 x 20 and 5 x 10

the scale factor us 10/5 = 20/10 = 2

Hope this helps.

4 0

2 years ago

if the speed of sound is 344 meters per second, what is the approximate speed of sound, in meters per hour?

choli [55]

Since we already know that the speed of sound is 344m per second, there are 60 seconds in one minute, and there are 60 minutes in one hour, we just multiply 344 by 60, giving us 20,640. Then we multiply 20,640 by 60 to get an answer of 1,238,400 meters per hour.

4 0

3 years ago

If an = 2n - 3, then what is the fifth term of the sequence?

boyakko [2]

Answer:

Step-by-step explanation:

To find the fifth term in the sequence, plug in 5 for n.

a₅=2(5)-3

Then just solve

a₅=10-3

a₅=7

3 0

2 years ago

Read 2 more answers

If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=

Alexxx [7]

$\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\$

$\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}$

now, if we just knew what g(2) is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that means if we use that value in f(x), f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus 2 = 2x+sin(x)

$\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}$

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it

5 0

2 years ago

Teresa drove on monday tuesday and Wednesday. On monday her driving distance was 120 miles. The ratio of Wednesdays distance is

SSSSS [86.1K]

Answer:

Teresa drive <u>90 miles</u> on Tuesday.

Step-by-step explanation:

Given:

Teresa drove on Monday, Tuesday and Wednesday.

On monday her driving distance was 120 miles.

The ratio of Wednesdays distance is 3/5.

The ratio of Wednesdays distance to Tuesday's distance is 5/4.

Now, to find the miles Teresa drive on Tuesday:

Teresa driving distance on Monday was = 120 miles.

Her driving distance on Wednesday is = $\frac{3}{5}\ of\ 120.$

$=\frac{3}{5} \times 120\\\\=0.6\times 120\\\\=72\ miles.$

Now, her driving distance on Tuesday is:

$\frac{5}{4} \ of\ 72\\\\=\frac{5}{4} \times 72\\\\=1.25\times 72\\\\=90\ miles.$

Therefore, Teresa drive 90 miles on Tuesday.

7 0

3 years ago