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kumpel [21]
3 years ago
14

A 1970 comic book originally sold for $0.35 has appreciate 10% per year. What will it be worth this year? Round to the nearest c

ent.
Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

$41.09 (as of 2020)

Step-by-step explanation:

i took the test

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What is the product?<br> (2x-1)(x+4)<br> 2x²-4<br> 0<br> 2x²+4<br> 0<br> 2x² + 7x-4<br> 2x² – 7x-4
vladimir2022 [97]

Answer:

C) 2x^2+7x-4

Step-by-step explanation:

(2x-1)(x+4)=2x^2-x+8x-4=2x^2+7x-4

3 0
3 years ago
Read 2 more answers
Show me how to get this answer show your work
Rama09 [41]

We know that angle MKJ is comprised of angle MKL and angle LKJ. That means if we add MKL and LKJ, we should get 80 degrees, which is the measure of angle MKJ.

MKL + LKJ= MKJ \implies \\ 2x+10+3x-5=80 \implies \\ 5x+5=80 \implies\\ 5x=75 \implies \\ x=15

So, we know that our x is 15. That is not enough to tell whether KL is an angle bisector, because we have to evaluate both MKL and LKJ with x=15, so:

MKL=2(15)+10 = 40\\ LKJ=3*15-5=40

So we see that these two angles are actually bisectors, and the third question best describes this phenomenon.

6 0
3 years ago
Read 2 more answers
First one to answer receives 100 points and brainiest!
larisa [96]

Answer and Step-by-step explanation:

<em>116 b.</em>

2^{10} = 1024\\2^8 = 256\\\\1024 + 256 = 1280\\\\\\2^5 = 32\\2^3 = 8\\\\32 - 8 = 24

1280 × 24 = 30720

<u>30720 ÷ 60 = 512. 512 is the solution; the expression is divisible by 60.</u>

<em>116 c.</em>

16^3 = 4096\\8^3 = 512\\\\4096 - 512 = 3584\\\\\\4^3 = 64\\2^3 = 8\\\\64 + 8 = 72

3584 × 72 = 258048

<u>258048 ÷ 60 = 4096. 4096 is the solution; the expression is divisible by 63.</u>

<em>116 d.</em>

125^2 = 15625\\25^2 = 625\\\\15625 + 625 = 16250\\\\\\5^2 = 25\\\\25 - 1 = 24

16250 × 24 = 390000

<u>390,000 ÷ 39 = 10,000. 10,000 is the solution; the expression is divisible by 39.</u>

<u></u>

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<em><u>#teamtrees #PAW (Plant And Water)</u></em>

4 0
3 years ago
High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample  'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2}  + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )

(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

4 0
3 years ago
Find the standard deviation of
Kruka [31]

Answer:

11.5

The sample standard deviation measures the spread of a data distribution of the sample. It is usually used to estimate the population standard deviation

7 0
3 years ago
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